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3 years ago

The equilibrium constant, Kc, for the following

Chemistry

1 answer:

umka21 [38]3 years ago

4 0

Answer:

2CH2Cl2(g) Doublearrow CH4(g) + CCl4(g)

0.205 moles of CH2Cl2 is introduced. Let by the time an equilibrium is reached x moles each of CH4 and CCl4 are formed => remaining moles of CH2Cl2 are 0.205-x

i.e at equilibrium the concentration on CH2Cl2 is (0.205-2x) mol/L, CH4 is x mol/L, CCl4 is x mol/L

Now the equilibrium constant equation : K = [CH4][CCl4]/[CH2Cl2]^2 ([.] - stands for concentration of the term inside the bracket)

10.5 = x*x/(0.205-2x)^2

=> 10.5(4x^2-0.82x+0.042) = x^2

=>42x^2-8.61x+0.441=x^2

=>41x^2-8.61x+0.441 = 0

This is a Quadratic in x, solving for the roots, we get x = 0.0886 , x = 0.121

The second solution for x will lead 0.205-2x to become negative, so is an infeasible solution.

Therefore equilibrium concentrations of the products and reactants correspond to x=0.0886 and they are , [CH2Cl2] = 0.205-2*0.0886 =0.0278 mol/L , [CH4] = 0.0886 mol/L , [CCl4] = 0.0886 mol/L

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Every reduction reaction MUST be accompanied by

Dafna1 [17]

Answer:

oxidation reaction.

Explanation:

Every reduction reaction must be accompanied by an oxidation reaction.

Oxidation leads electrons loss whereas reduction implies gain of electrons. So missing electrons should always be the equivalent of obtained electrons. Without something acquiring electrons there can't be any loss. Electrons can't simply disappear!

It implies, but, that oxidation and reduction must occur simultaneously at different locations and the electrons can commute across cables or in a liquid medium by ions.

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3 years ago

Find the mass of 3.21 x 10^-2 Nickel

Karo-lina-s [1.5K]

Answer:

1.88 g

Explanation:

n(moles) = mass/molar mass

mass = moles x molar mass of nickel

mass = 3.21x10^-2 x 58.69

mass = 1.883949 grams

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3 years ago

The diatomic molecule of chlorine, cl2, is held together by a(n)____ covalent bond.

kvasek [131]

Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.

Covalent Bond :

It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .

Formation of covalent bond in Cl₂ :

Chlorine is present in group 17 in p block , It is a non metal .

The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .

Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .

From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .

Now the octet of both the atom are complete and they are in stable state together .

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Cl + Cl -> Cl₂

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4 years ago

How much of a 15.0M stock solution do you need to prepare 250ml of a 2.35ml hf solution?

Svetradugi [14.3K]

Using the relationship M1V1 = M2V2 where M1 and M2 are the molar concentrations (mol/L or mmol/ml) and V1 and V2 are the volumes of the solutions, we can arrive at the following answer for the given problem:

<span>15.0M (L of stock solution) = 2.35M (0.25L) *all volumes were converted to liters.

L of stock solution = (2.35*0.25)/15.0

Therefore, 0.0392L or 39.17 ml of stock solution is needed. </span>

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3 years ago

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rewona [7]

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