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3 years ago

The equilibrium constant, Kc, for the following

Chemistry

1 answer:

umka21 [38]3 years ago

4 0

Answer:

2CH2Cl2(g) Doublearrow CH4(g) + CCl4(g)

0.205 moles of CH2Cl2 is introduced. Let by the time an equilibrium is reached x moles each of CH4 and CCl4 are formed => remaining moles of CH2Cl2 are 0.205-x

i.e at equilibrium the concentration on CH2Cl2 is (0.205-2x) mol/L, CH4 is x mol/L, CCl4 is x mol/L

Now the equilibrium constant equation : K = [CH4][CCl4]/[CH2Cl2]^2 ([.] - stands for concentration of the term inside the bracket)

10.5 = x*x/(0.205-2x)^2

=> 10.5(4x^2-0.82x+0.042) = x^2

=>42x^2-8.61x+0.441=x^2

=>41x^2-8.61x+0.441 = 0

This is a Quadratic in x, solving for the roots, we get x = 0.0886 , x = 0.121

The second solution for x will lead 0.205-2x to become negative, so is an infeasible solution.

Therefore equilibrium concentrations of the products and reactants correspond to x=0.0886 and they are , [CH2Cl2] = 0.205-2*0.0886 =0.0278 mol/L , [CH4] = 0.0886 mol/L , [CCl4] = 0.0886 mol/L

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3 years ago

Assuming 100% dissociation, calculate the freezing point and boiling point of 3.11 m K3PO4(aq). Constants may be found here.

aivan3 [116]

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3 years ago

`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma

Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

$2Al + 6HCl\rightarrow 2AlCl_3 +3H_2$

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when $\frac{2}{3}$ moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when $\frac{2}{3}\times 10.0$ moles of aluminium undergoes reaction.

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6 0

3 years ago

What is the molarity of NO−3 in 0.160M KNO3?

zubka84 [21]

A solution of KNO3 consists of ions of potassium and nitrate. The ionic equation is expressed as:

KNO3 = K+ + NO3-

There is 1 is to 1 ratio between the substances. So, the molarity of NO3- in the solution is calculated as follows:

0.160 mol / L KNO3 ( 1 mol NO3- / 1 mol KNO3 ) = 0.160 M NO3-

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3 years ago

Under certain conditions, the substance ammonium chloride can be broken down to form ammonia and hydrogen chloride. If 29.4 gram

lina2011 [118]

Answer: 20.0 g of hydrogen chloride must simultaneously be formed

Explanation:

The balanced chemical reaction is :

$NH_4Cl\rightarrow NH_3+HCl$

According to the law of conservation of mass, mass can neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side.

Thus mass of reactants = mass of products

Given : mass of ammonium chloride = mass of reactants = 29.4 g

mass of ammonia = 9.4 g

mass of products = mass of ammonia + mass of hydrogen chloride

9.4 g +mass of hydrogen chloride = 29.4 g

mass of hydrogen chloride = 20.0 g

5 0

3 years ago