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Aneli [31]
2 years ago
15

A scientist mixes a solid powder into a beaker

Chemistry
1 answer:
faust18 [17]2 years ago
5 0
The question doesn’t make sense sorry
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How many grams are there in a 14.5 moles lithium permanganate
frutty [35]

There are 1825.6 g in a 14.5 moles Lithium permanganate

<h3> Further explanation</h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass :

\tt mol=\dfrac{mass}{MW}

moles of Lithium permanganate = 14.5

Lithium permanganate (LiMnO4) MW=125.9 g/mol, so mass :

\tt mass=mol\times MW\\\\mass=14.5\times 125.9~g/mol\\\\mass=1825.6~g

5 0
3 years ago
What is the area beyond the black hole where the black hole has stopped expanding and matter will no longer be pulled in?
gregori [183]
C. dk I’m just trying to get points sorry
7 0
2 years ago
Atomic mass unit is calculated with reference to
Gennadij [26K]
An atomic mass unit is defined as a mass equal to one twelfth the mass of an atom of carbon-12. The mass of any isotope of any element is expressed in relation to the carbon-12 standard. For example, one atom of helium-4 has a mass of 4.0026 amu. An atom of sulfur-32 has a mass of 31.972 amu.
8 0
2 years ago
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When the weather change and temperatures get hot what do wolves use to cool down
shusha [124]
When the seasons change from winter to spring, the wolves inner layer of fur, which traps air and insulates the wolf from harsh cold temperatures, is shed to keep the wolf cool when the heat starts to come back. 
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2 years ago
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What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)
Slav-nsk [51]

Given :

Molarity of sulfuric acid solution is 3.0 M.

Amount of sulfuric acid present in solution is 9.809 g.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

Molarity = \dfrac{number \ of \ moles \times 1000}{Volume\ ( ml )}\\\\M = \dfrac{w \times 1000}{M.M \times V}\\\\3 = \dfrac{9.809\times 1000}{98.09 \times V}\\\\V = \dfrac{1000}{10\times 3}\  ml\\\\V = 33.33 \ ml

Therefore, volume required is 33.33 ml .

5 0
3 years ago
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