Answer:
I2 + 2S2O3^2- --------> S4O6^2- + 2I^-
Explanation:
The correct equation is;
2Na2S2O3 + I2 → Na2S4O6 + 2NaI
Oxidation half equation;
2S2O3^2- --------> S4O6^2- + 2e-
Reduction half equation;
I2 + 2e ----------> 2I^-
Overall balanced redox reaction equation;
I2 + 2S2O3^2- --------> S4O6^2- + 2I^-
Answer:
102
Explanation:
(20+1+30)*2
you add the total number of atoms that can be found in one molecule of vitamin A then multiply by 2
KOH is a compound containing two ions, K+ and OH-.
<span>The polyatomic ion present is OH- which is called hydroxide. </span>
<span>The compound is named potassium hydroxide.</span>
1. B. Liquid
2. C. both A & B
3. C. Indefinite shape and definite volume
4. D. Sublimation
5. Its gotta either be B or D its most likely D
6. A. Neutron
7. D.12
8. C. Ground State
9. C. Synthesis reaction
10. D. None of the above
11. Both A and C
12. A. 2
13. A. Element
14. A. Cu
15. D. Periods, Groups
16. B. Metals, Non-metals
17. A. F
18. D. None of the above
19. Either B or D
20. B. H-2.06% S-32.6% O-65.3%
21. A. Na2SO4
22. C. Combustion reaction
23. if I'm correct it should be C. Nitrogen Bromide
24. Sorry not sure what the answer is but your welcome I hope the rest of theses help!!
Reaction of Copper with Mercuric Nitrate is as follow,
Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg
According to equation,
1 Mole of Cu reacts to form = 1 Mole of Hg
So,
1.20 Moles of Cu will react to produce = X Moles of Hg
Solving for X,
X = (1.20 mol × 1 mol) ÷ 1 mol
X = 1.20 mol of Hg
Result:
1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
