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Wewaii [24]
3 years ago
11

An old rectangular tank with length 0.3 m could hold 154 L of water. A new similar tank has a length of 1.5 m. What is the capac

ity of the new tank?
Mathematics
2 answers:
dimaraw [331]3 years ago
6 0
The length of the new tank is 5 times bigger than the old one, so 154×5=770. As a result, the capacity of the new tank is 770L. Hope it help!
zimovet [89]3 years ago
5 0
You can use a proportion for this problem.  First, always make sure that the units are the same in both scenarios.  Then you can set up the proportion: (given m of old tank)/(given L of old tank)=(given m of new tank)/x   Let x represent the L in the new tank.  Then cross multiply to solve the proportion.
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144

Step-by-step explanation:

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3. In AABC, a = 35, c = 25, and m can be drawn given these measurements?
Flauer [41]

Only one triangle possible with angle 38.2° at C.

According to the given statement

we have to seek out that the measurement of m with the help of the a and c.

Then for this purpose, we all know that the

The ambiguous case occurs when one uses the law of sines to see missing measures of a triangle when given two sides and an angle opposite one in every of those angles (SSA).

According to the this law

The equation become

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sinC = 0.6185895741

C = 38.2, 141.8

Since 141.8+60 = 201.8 > 180

It will not form a triangle.

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Learn more about ambiguous case here

brainly.com/question/4372174

#SPJ1

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =35, c = 25, and m < A = 60*

How many distinct triangles can be drawn given these measurements?

6 0
10 months ago
What us the length of the longer side?
julsineya [31]
The perimeter:
P=2\cdot(3x+3)+2\cdot2x=6x+6+4x=10x+6\\\\P=146\ units\to10x+6=146\ \ \ |-6\\\\10x=140\ \ \ |:10\\\\x=14\ units
The length of the longer side:
3x+3=3\cdot14+3=42+3=45\ units

3 0
3 years ago
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