Answer:
Explanation:
This problem is based on conservation of rotational momentum.
Moment of inertia of rod about its center
= 1/12 m l² , m is mass of the rod and l is its length .
= 1 / 12 x 4.6 x .11²
I = .004638 kg m²
The angular momentum of the bullet about the center of rod = mvr
where m is mass , v is perpendicular component of velocity of bullet and r is distance of point of impact of bullet fro center .
5 x 10⁻³ x v sin60 x .11 x .5 where v is velocity of bullet
According to law of conservation of angular momentum
5 x 10⁻³ x v sin60 x .11 x .5 = ( I + mr²)ω , where ω is angular velocity of bullet rod system and ( I + mr²) is moment of inertia of bullet rod system .
.238 x 10⁻³ v = ( .004638 + 5 x 10⁻³ x .11² x .5² ) x 12
.238 x 10⁻³ v = ( .004638 + .000015125 ) x 12
.238 x 10⁻³ v = 55.8375 x 10⁻³
.238 v = 55.8375
v = 234.6 m /s
Answer:
13.8 N
Explanation:
Pressure on the one end of the hydraulic system = Pressure on the other end
Pressure = Force / Area where Force is in Newton, area is in m²
so Force of one end (F1) / area of that end = force of the other end (F2) / area of that end
3112 / ( 707 /10000) in m² = F2 / ( 3.14 / 10000) in m²
cross multiply
44016.97 × 0.000314 = 13.82 N
Answer: Actually three of them are. The ovaries, the uterus and fallopian tubes.
Answer:
Answer is D. a north pole is near a south pole
Explanation:
Hope this helps!! :D
