Answer:
2.55 m
Explanation:
Elastic energy = gravitational energy
½ kx² = mgh
h = kx² / (2mg)
h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)
h = 2.55 m
The frequency of a wave is just the reciprocal of the period.
For this one . . .
Frequency = 1/(period) = 1/(5 sec) = 0.2 per sec (0.2 Hz) .
Yes! you are :) bc you are FORCING the page to turn, and the broom ti sweep
Answer:
v = 6.45 10⁻³ m / s
Explanation:
Electric force is
F = q E
Where q is the charge and E is the electric field
Let's use Newton's second law to find acceleration
F- W = m a
a = F / m - g
a = q / m E g
Let's calculate
a = -1.6 10⁻¹⁹ / 9.1 10⁻³¹ (-1.30 10⁻¹⁰) - 9.8
a = 0.228 10² -9.8
a= 13.0 m / s²
Now we can use kinematics, knowing that the resting parts electrons
v² = v₀² + 2 a y
v =√ (0 + 2 13.0 1.6 10⁻⁶)
v = 6.45 10⁻³ m / s
Explanation:
It is given that,
A particle starts from rest and has an acceleration function as :

(a) Since, 
v = velocity




(b) 
x = position



(c) Velocity function is given by :


t = 1 seconds
So, at t = 1 second the velocity of the particle is zero.