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Sedbober [7]
2 years ago
15

Two magnets are arranged so that they pull together. Which conclusion can be reached? A.Two north poles are together. B. Two sou

th poles are together. C. The poles of the magnets are touching. D. A north pole is near a south pole.
Physics
2 answers:
Virty [35]2 years ago
6 0

Answer:

Answer is D. a north pole is near a south pole

Explanation:

Hope this helps!! :D

Tema [17]2 years ago
6 0
D because opposites attract :)
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How long does it take for a 3.5 kW electric water heater to heat 40 kg of water? from 20 ° C to 75 ° C? The specific heat capaci
iren [92.7K]

Answer:

2633.7 s

Explanation:

From the question,

Heat lost by the water heater = Heat gained by the water

Applying,

P = cm(t₂-t₁)/t.................. Equation 1

Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time

make t the subject of the equation

t = cm(t₂-t₁)/P.............. Equation 2

From the question,

Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C

Substitute these values into equation 2

t = 4190×40(75-20)/3500

t = 9218000/3500

t = 2633.7 s

4 0
3 years ago
0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary for
Paladinen [302]

Assuming the accleration applied was constant, we have

v=v_0+at\implies v_0+20.0\,\dfrac{\mathrm m}{\mathrm s}=v_0+a(0.10\,\mathrm s)

\implies20.0\,\dfrac{\mathrm m}{\mathrm s}=a(0.10\,\mathrm s)

\implies a=200\,\dfrac{\mathrm m}{\mathrm s^2}

Then the force applied to the ball is given by

F=ma=(0.45\,\mathrm{kg})\left(200\,\dfrac{\mathrm m}{\mathrm s^2}\right)

\implies F=90\,\dfrac{\mathrm{kg}\,\mathrm m}{\mathrm s^2}=90.\,\mathrm N

8 0
3 years ago
Rahul has 2 bulbs connected across two cells in a simple circuits shown. How can he make the bulbs glow dimmer?
Ray Of Light [21]

Answer:

in the parallel connection the light bulbs shine less than in the series connection

Explanation:

In a series circuit the current through the whole circuit is the same, therefore the power (brightness) of each bulb is

           P = i² R

where R is the resistance of each bulb and i the current of the circuit.

If we connect the light bulbs and the cells in parallel, the current in the circuit is the sum of the east that passes through each light bulb,

            i = i₁ + i₂

if the two light bulbs are the same

           i = 2 i₁

           i₁ = i / 2

so the power of each bulb is is

           P = i₁² R

           P = R i² / 4

           P = ¼ P_initial

Therefore we see that in the parallel connection the light bulbs shine less than in the series connection

3 0
3 years ago
An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V, at a phase angle of +32.6°. When the potentia
Reil [10]

Answer:

V=-8.35v

Explanation:

Pls see attached file

6 0
3 years ago
A 2.0 m length of wire is made by welding the end of a 120 cm long silver wire to the end of an 80 cm long copper wire. Each pie
Levart [38]

<u>Explanation</u>:

Resistivity of silver wire =1.47 e-8 ohm meter

Resistivity of copper wire = 1.72 \mathrm{e}-8 \text { ohm meter }

Resistance = Resistivity *length/cross sectional area

R=\rho_{L / A}

So,

\begin{aligned}&I=A\left(V / P_{A g} L_{A g}+P_{C u} L C_{U}\right)\\&1=8104 \mathrm{A}\end{aligned}

For E calculation

For copper

E = resistivity * current density

E = Resistivity * current/area

E=4.9298 \mathrm{V} / \mathrm{m}

For silver

E=4.213 \mathrm{V} / \mathrm{m}

Potential difference $=E^{*} L$

For silver

Potential difference = 4.213^{*} 1.2=5.055 \mathrm{V}

For copper

Potential difference =3.9438 \mathrm{V}

7 0
3 years ago
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