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Mila [183]
2 years ago
9

A sports car starts from rest it covers a distance of 900 m to attain a speed of 80m s determine the acceleration of the car and

the time required to reach this speed
Physics
1 answer:
Lady bird [3.3K]2 years ago
5 0

The acceleration of the car and the time required to reach this speed will be 8 m/s² and 10 sec.

<h3>What is acceleration?</h3>

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u=0  m/s

Final velocity, v= 80 m/sec

Distance travelled,s =900m

From Newton's third equation of motion;

v²=u²+2as

a =(v²-u²)/2s

Substitute the given values;

a = (80²-0)/2 ×900

a = 6400/1800

a=8 m/s²

The time required to reach this speed is found in Newton's first equation of motion as;

v = u+at

Substitute the given values;

80 = 0 + 8t

t=80/8

t = 10 sec

Hence, the acceleration of the car and the time required to reach this speed will be 8 m/s² and 10 sec.

To learn more about acceleration, refer to the link brainly.com/question/2437624

#SPJ1

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A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What
nika2105 [10]

Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².

Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.

Given,

Radius of flywheel (r) = 1.96 cm = 0.0196m

Angular acceleration (α)= 13.0 rad/s²

The tangential acceleration formula is at=rα

where, α is the angular acceleration, and r is the radius of the circle.

using the formula; at=rα  = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².

The tangential acceleration is 0.2548 m/s².

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brainly.com/question/15743294

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5 0
1 year ago
A conducting sphere of radius r1 = 0.21 m has a total charge of Q = 2.9 μC. A second uncharged conducting sphere of radius r2 =
wolverine [178]

Answer:

what is the anser

Explanation:

4 0
3 years ago
What is the voltage drop across the 10.0 2 resistor?
amid [387]

Answer:

the answer is equal to 2.00v

4 0
3 years ago
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag
CaHeK987 [17]

The speed of tsunami is a.0.32 km. 

Steps involved  :

The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

To learn more about tsunami refer : brainly.com/question/11687903

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6 0
2 years ago
When water freezes, its volume increases by 9.05% (that is, equation). What force per unit area is water capable of exerting on
PIT_PIT [208]

Answer:

1.991 × 10^(8) N/m²

Explanation:

We are told that its volume increases by 9.05%.

Thus; (ΔV/V_o) = 9.05% = 0.0905

To find the force per unit area which is also pressure, we will use bulk modulus formula;

B = Δp(V_o/ΔV)

Making Δp the subject gives;

Δp = B(ΔV/V_o)

Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²

Thus;

Δp = 2.2 × 10^(9)[0.0905]

Δp = 1.991 × 10^(8) N/m²

3 0
3 years ago
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