Distilled water.high school Lab
Answer:
52.99 kPa
Explanation:
Initial volume V1 = 2.7 L
Initial Pressure P1 = 78.5 kPa
Final Volume V2 = 4.0L
Final Pressure P2 = ?
Temperature is constant
The relationship between these quantities is given by the mathematical expression of Boyles law. This is given as;
V1P1 = V2P2
P2 = V1P1 / V2
P2 = 2.7 * 78.5 / 4.0
P2 = 52.99 kPa
Answer:
b melting
Explanation:
The phase change the substance is undergoing is from solid to liquid and this is called melting.
- To understand this process, we need to know the the substance changing.
- A substance that contains particles that are not easily compressed and packed is a solid.
- Solids have fixed shapes and volumes.
- Liquids can easily flow although they cannot also be easily compressed.
The phase change from solid to liquid is facilitated by a melting process.
Explanation:
The solubility curve helps us to compare the solubility of difference substances at same temperature. It gives the idea that solubility changes with the temperature. The solubility curve helps us to predict which substance will crystalize out first from hot solution containing two or more solutes.
Answer : The correct option is, (2) Fission reaction.
Explanation :
- Fission reaction : This is a type of nuclear reaction in which the splitting of bigger nuclei into two smaller nuclei takes place. During this process, the large amount of energy is released.
- Redox reaction : This is an oxidation-reduction reaction in which the electrons transferred between the two molecules.
- Substitution reaction : In this reaction, one functional group is replaced by the another functional group in a chemical compound.
- Neutralization reaction : In this reaction, the acid and base react to give water and a salt.
Redox reaction, substitution reaction and neutralization reaction are the chemical reactions in which the heat releases when the chemical bonds are breaking and forming.
Therefore, the greatest amount of energy released per gram of reactants occurs during the fission reaction.
