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Elanso [62]
3 years ago
13

Which object would be the best insulator of electricity?

Physics
2 answers:
solniwko [45]3 years ago
7 0

Answer:

a rubber band

Explanation:

hope this helps!

Gelneren [198K]3 years ago
4 0

Answer:

a rubber band

Explanation:

thank you

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An airplane is flying in air with a density of 1.29 kg/m3. A pressure gauge measures
jeka57 [31]

Answer:

341 m/s

Explanation:

Use Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Assuming no elevation change, h₁ = h₂.

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

The velocity of the air at the nose is 0 m/s, so:

P₁ = P₂ + ½ ρ v₂²

ΔP = ½ ρ v₂²

Plugging in values:

75000 Pa = ½ (1.29 kg/m³) v²

v = 341 m/s

5 0
3 years ago
Superman throws a 2400 n boulder at a villain. what horizontal force must superman apply to the boulder to give a horizontal acc
Ksenya-84 [330]
The boulder has a weight of W=2400 N. The weight of an object is the product between its mass m and the gravitational acceleration g:
W=mg
Rearranging the relationship, we can calculate the mass of the boulder:
m= \frac{W}{g}= \frac{2400 N}{9.81 m/s^2}=244.6 kg

We are told that Superman applies a horizontal force to this object, and as a result, the acceleration of the boulder is a=12.0 m/s^2. We can find the force applied by using Netwon's second law of motion:
F=ma=(244.6 kg)(12.0 m/s^2)=2935 N
4 0
3 years ago
Which of the following occurs in meiosis that does not occur in mitosis
Elanso [62]

3) sex cells are made

8 0
4 years ago
Plz Helpp
marshall27 [118]

300

could i get brainiest

5 0
3 years ago
A circuit with a lagging 0.7 pf delivers 1500 watts and 2100VA. What amount of vars must be added to bring the pf to 0.85
kvasek [131]

Answer:

\mathtt{Q_{sh} = 600.75 \ vars}

Explanation:

Given that:

A circuit with a lagging 0.7 pf delivers 1500 watts and 2100VA

Here:

the initial power factor  i.e cos θ₁ = 0.7 lag

θ₁ = cos⁻¹ (0.7)

θ₁ = 45.573°

Active power P = 1500 watts

Apparent power S = 2100 VA

What amount of vars must be added to bring the pf to 0.85

i.e the required power factor here is cos θ₂ = 0.85 lag

θ₂ =  cos⁻¹   (0.85)

θ₂ = 31.788°

However; the initial reactive power Q_1 = P×tanθ₁

the initial reactive power Q_1 = 1500 × tan(45.573)

the initial reactive power Q_1 = 1500 × 1.0202

the initial reactive power Q_1 =  1530.3 vars

The amount of vars that must therefore be added to bring the pf to 0.85

can be calculated as:

Q_{sh} = P( tan \theta_1 - tan \theta_2)

Q_{sh} = 1500( tan \ 45.573 - tan \ 31.788)

Q_{sh} = 1500( 1.0202 - 0.6197)

Q_{sh} = 1500( 0.4005)

\mathtt{Q_{sh} = 600.75 \ vars}

3 0
3 years ago
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