Answer:
341 m/s
Explanation:
Use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Assuming no elevation change, h₁ = h₂.
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
The velocity of the air at the nose is 0 m/s, so:
P₁ = P₂ + ½ ρ v₂²
ΔP = ½ ρ v₂²
Plugging in values:
75000 Pa = ½ (1.29 kg/m³) v²
v = 341 m/s
The boulder has a weight of W=2400 N. The weight of an object is the product between its mass m and the gravitational acceleration g:

Rearranging the relationship, we can calculate the mass of the boulder:

We are told that Superman applies a horizontal force to this object, and as a result, the acceleration of the boulder is

. We can find the force applied by using Netwon's second law of motion:
Answer:

Explanation:
Given that:
A circuit with a lagging 0.7 pf delivers 1500 watts and 2100VA
Here:
the initial power factor i.e cos θ₁ = 0.7 lag
θ₁ = cos⁻¹ (0.7)
θ₁ = 45.573°
Active power P = 1500 watts
Apparent power S = 2100 VA
What amount of vars must be added to bring the pf to 0.85
i.e the required power factor here is cos θ₂ = 0.85 lag
θ₂ = cos⁻¹ (0.85)
θ₂ = 31.788°
However; the initial reactive power
= P×tanθ₁
the initial reactive power
= 1500 × tan(45.573)
the initial reactive power
= 1500 × 1.0202
the initial reactive power
= 1530.3 vars
The amount of vars that must therefore be added to bring the pf to 0.85
can be calculated as:




