<span>(Y-3)^2 = 4y -12 <=> Y^2 - 6Y + 9 = 4y - 12 <=> 4y = Y^2 - 6Y + 21 <=> y = (Y^2 - 6Y + 21)/4. Solving the equation for y means that we have to express y relative to the other quantities in the equation.</span>
Answer:
The radius of hole is 5 feet
Step-by-step explanation:
Depth of conical hole = 9 feet
Let the radius of hole be r
Volume of conical hole =![\frac{1}{3} \pi r^2 h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2%20h)
So, Volume of conical hole =![\frac{1}{3} \pi \times r^2 \times 9](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20%5Ctimes%20r%5E2%20%5Ctimes%209)
We are given that volume of a CONE-shaped hole is 75pi ft cubed.
So,![\frac{1}{3} \pi \times r^2 \times 9=75 \pi](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20%5Ctimes%20r%5E2%20%5Ctimes%209%3D75%20%5Cpi)
![\frac{1}{3} \times r^2 \times 9=75](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%20r%5E2%20%5Ctimes%209%3D75)
![r^2=\frac{75 \times 3}{9}](https://tex.z-dn.net/?f=r%5E2%3D%5Cfrac%7B75%20%5Ctimes%203%7D%7B9%7D)
![r=\sqrt{\frac{75 \times 3}{9}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%5Cfrac%7B75%20%5Ctimes%203%7D%7B9%7D%7D)
r=5
Hence The radius of hole is 5 feet
Answer:
In Triangle FGH, m<F = 42 and an exterior angle at vertex H as a measure of 104. What is the measure of <G?
Step-by-step explanation:
Answer: You are right it is 6
Step-by-step Explanation
Every circle counts as one so it is 6
BTW how do you make the picture appear
Divide it into two squares.
The first square is just (1)1, which equals 1 cm^2, and add that to the second square, which is just (2)2, which equals 4, so 1+4=5 cm^2.