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2 years ago

Type the correct answer in each box. Round your answers to the nearest hundredth.

Physics

1 answer:

Natali [406]2 years ago

8 0

The velocity of the ball at position A is 3.13 m/s.Since all energy is converted to KE.

<h3>What is potential energy?</h3>

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.

A person has the most potential energy due to her position. when he is sitting on the highest point.

Given data;

Mass,m = .5 kg

Height,H = 0.5 m

Acceleration due to gravity,g = 9.8 m/s²

H is the height

The potential energy is found as;

The potential energy is mainly dependent upon the height of the object.

Potential energy = mgh

The potential energy at point B;

PE = mgh

PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)

PE = 7.35 J

Since all energy is converted to KE, the kinetic energy at point B;

KE = 0.5mv^2

KE = PE

7.35 = 0.53(1.5) v^2

V = 3.13 m/s

Hence, the velocity of the ball at position A is 3.13 m/s.

To learn more about the potential energy, refer to the link;

brainly.com/question/24284560

#SPJ1

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Answer:

a) $v=13.2171\,m.s^{-1}$

b) $H=8.9605\,m$

Explanation:

Given:

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(a)

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$F=m.a$

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$a\approx 1835\,m.s^{-2}\\$

we have:

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Using the eq. of motion:

$v^2=u^2+2a.\Delta x$

where:

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$v^2= 0^2+2\times 1835\times 0.0476$

$v=13.2171\,m.s^{-1}$

(b)

Now, in vertical direction we take the above velocity as the initial velocity "u"

so,

$u=13.2171\,m.s^{-1}$

∵At maximum height the final velocity will be zero

$v=0\,m.s^{-1}$

Using the equation of motion:

$v^2=u^2-2g.h$

where:

h= height

g= acceleration due to gravity

$0^2=13.2171^2-2\times 9.8\times h$

$h=8.9129\,m$

is the height from the release position of the spring.

So, the height from the latched position be:

$H=h+\Delta x$

$H=8.9129+0.0476$

$H=8.9605\,m$

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a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its potential energy (PE) when it is 2.00 m above the grou

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Answer:

1.56 J

Explanation:

The potential energy only depends on the vertical height from the ground level.

We consider the ground level to have zero P.E.

So when it is 2 m above the ground level,

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L = (T/2π)²g

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