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2 years ago

2 ways to change frictional force between 2 objects

2 answers:

8 0

It can be changed by shorter distances and by the amount of weight it has or the amount of force that is pushing that object to go however distance it can.

Zanzabum2 years ago

5 0

In order to change the frictional force between two solid surfaces, it can be changed by shorter distances and by the amount of weight it has or the amount of force that is pushing that object to go however distance it can.

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A boy im50kg at rest on a skateboard is pushed by another boy who exerts a force of 200 N on him. If the first boy's

sergey [27]

Answer:

Time, t = 2 seconds

Explanation:

Given the following data;

Mass, m = 50 kg

Initial velocity, u = 0 m/s (since it's starting from rest).

Final velocity, v = 8 m/s

Force, F = 200 N

To find the time, we would use the following formula;

$F = \frac {m(v - u)}{t}$

Making time, t the subject of formula, we have;

$t = \frac {m(v - u)}{F}$

Substituting into the formula, we have;

$t = \frac {50(8 - 0)}{200}$

$t = \frac {50*(8)}{200}$

$t = \frac {400}{200}$

Time, t = 2 seconds

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2 years ago

A coastal forest was home to a type of burrowing rodent that was not found anywhere else in the world. A year ago, a species of

Lapatulllka [165]

Answer:A

Explanation: just took it on E 2020

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2 years ago

A tightly sealed glass jar is an example of which type of system?

noname [10]

D. hope it helps. :D

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2 years ago

Read 2 more answers

During combustion reactions, explain why the energy of the reactants must exceed the total energy of the products

maxonik [38]

Answer:

In these reactions the products are higher in energy than the reactants. ... This barrier is due to the fact that to make CO2 and H2O we have to break 4 carbon-hydrogen bonds and some ...

Explanation:

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2 years ago

9. A wave on Beaver Dam Lake passes by two docks that are 40.0 m apart.

Kobotan [32]

Answers:

a) 10 m

b) time=1.6 s, frquency=0.625 Hz

c) 6.25 m/s

Explanation:

a) If there is a crest at each dock and another three crests between the two docks, and the wavelength $\lambda$ is the distance between to crests; this means we have $4\lambda$ in $40 m$ :