All categories

3 years ago

What is the volume of a cube whose side is 10 cm?

Physics

2 answers:

anyanavicka [17]3 years ago

6 0

the first one Is right answer

Rasek [7]3 years ago

5 0

<u>Answer:</u> The volume of the cube is $10^{-3}m^3$

<u>Explanation:</u>

To calculate the volume of cube, we use the formula:

$V=a^3$

where,

a = edge length of cube = 10 cm = 0.1 m (Conversion factor: 1 m = 100 cm)

Putting values in above equation, we get:

$V=(0.1)^3=0.001m^3=10^{-3}m^3$

Hence, the volume of the cube is $10^{-3}m^3$

You might be interested in

Which of the following identifies the number of protons in an atom?

Lunna [17]

Answer:

The number of protons can be found by looking at the atomic number

Explanation:

Its at the very top of the little element box

8 0

3 years ago

One cycle of the power dissipated by a resistor ( R = 800 Ω R=800 Ω) is given by P ( t ) = 60 W , 0 ≤ t < 5.0 s P(t)=60 W, 0≤

OLga [1]

Answer:

42.5W

Explanation:

To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

We need to calculate the average power dissipated by the 800\Omega resistor.

Our values are given by:

$P(t)=60 W, 0\leq t$

$P(t)=25 W, 5.0\leq t$

Aplying the values to the equation we have:

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

$Power_{avg} = \frac{60(5-0)+25(10-5)}{(5-0)+(10-5)}$

$Power_{avg} = 42.5W$

5 0

3 years ago

It is very efficient to drive a large truck to and from school. Please select the best answer from the choices provided T F I th

cestrela7 [59]

It's 100% false, it wastes a ton (sorry for the bad pun!) of gas.

8 0

3 years ago

Read 2 more answers

A wedge shaped air film is made between two sheets of glass using a spacer at one end of the glass sheets. If light of wavelengt

pychu [463]

Answer:

1178 nm

Explanation:

We are given that

Wavelength of light= $\lambda=589nm=589\times 10^{-9} m$

$1nm=10^{-9} m$

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.

Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.

The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.

Change in air film thickness from one edge to other edge is same as the thickness of spacer.

Therefore, thickness of spacer= $2\lambda$

Thickness of spacer= $2\times 589\times 10^{-9}$ m

Thickness of spacer=1178 nm

Hence, the thickness of spacer=1178 nm

8 0

3 years ago

A car is stopped at a red light. When the light changes, the car begins to accelerate at a rate of 10 m/s^2 and it continues to

yaroslaw [1]

The velocity of the car after it accelerates for 25 seconds would be 820.2 ft/s or 250 m/s

4 0

3 years ago