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Shalnov [3]
3 years ago
13

What is the volume of a cube whose side is 10 cm?

Physics
2 answers:
anyanavicka [17]3 years ago
6 0

the first one Is right answer

Rasek [7]3 years ago
5 0

<u>Answer:</u> The volume of the cube is 10^{-3}m^3

<u>Explanation:</u>

To calculate the volume of cube, we use the formula:

V=a^3

where,

a = edge length of cube = 10 cm = 0.1 m     (Conversion factor: 1 m = 100 cm)

Putting values in above equation, we get:

V=(0.1)^3=0.001m^3=10^{-3}m^3

Hence, the volume of the cube is 10^{-3}m^3

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. Maria walked 1.5 miles south to her house in 0.5 hours. What is her speed in miles per hour?
Simora [160]

1) 3 miles/Hour

The speed is defined as the distance covered divided by the time taken:

v=\frac{d}{t}

where

d = 1.5 mi is the distance

t = 0.5 h is the time taken

Substituting,

v=\frac{1.5}{0.5}=3 mi/h

2) 1.34 m/s south

Velocity, instead, is a vector, so it has both a magnitude and a direction. We have:

d=1.5 mi \cdot 1609 m/mi = 2414 m is the displacement in meters

t=0.5 h \cdot 3600 s/h =1800 s is the time taken in seconds

Substituting,

v=\frac{2414 m}{1800 s}=1.34 m/s

And the direction of the velocity is the same as the displacement, so it is south.

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4 years ago
An archer pulls back the string of a bow to release an arrow at a target. Which kind of potential energy is transformed to cause
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Elastic Potential Energy because the elasticity in the string stores up the energy.
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4 years ago
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A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capaci
larisa [96]

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 =  e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

Learn more about energy stored in capacitor here: brainly.com/question/14811408

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2 years ago
A ball whose mass is 1.9 kg is suspended from a spring whose stiffness is 8.0 N/m. The ball oscillates up and down with an ampli
MArishka [77]

Answer:

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Explanation:

This is a simple harmonic motion. The angular frequency of a loaded spring is given by

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where k is the spring constant and m is the mass on the spring.

Using the known values,

\omega = \sqrt{\dfrac{8}{1.9}} = 2.05

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