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2 years ago

What does Newton’s law of universal gravitation say about the distance between objects?

1 answer:

3 0

Newton law of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

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A small ball of charge Q and mass m has a velocity v at infinity. It collides head-on with a ball of the same charge and mass wh

Hatshy [7]

Answer:

Explanation:

Kinetic energy of ball in motion = 1/2 m v² . Potential energy = 0

Let the minimum distance between the balls be d on collision.

Electric potential energy at that time= k Q²/d , Here kinetic energy is converted into potential energy . So

1/2 m v² = kQ²/d

d =2 k Q² / mv²,= 18 x 10⁹ x Q²/ m v².

8 0

3 years ago

Two friends, Al and Jo, have a combined mass of 195 kg. At the ice skating rink, they stand close together on skates, at rest an

ddd [48]

Answer:

Al's mass is 102.92 kg

Explanation:

As there are no external forces in the horizontal direction, the horizontal net force must be zero:

$F_{net} = 0$

As the force is the derivative in time of the momentum, this means that the horizontal momentum is constant:

$F_{net} = \frac{dp_{horizontal}}{dt} = 0$

$p_{horizontal_i }= p_{horizontal_f}$

where the suffix i and f means initial and final respectively.

The initial momentum will be:

$p_{horizontal_}i = m_{Al} \ v_{Al_i} + m_{Jo} \ v_{Jo_i}$

But, as they are at rest, initially

$p_{horizontal_i} = m_{Al} * 0 + m_{Jo} * 0$

$p_{horizontal_i} = 0$

So, this means:

$p_{horizontal_f} = m_{Al} \ v_{Al_f} + m_{Jo} \ v_{Jo_f} = 0$

We know that the have an combined mass of 195 kg:

$m_{total} = m_{Al} + m_{Jo} = 195 \ kg$ .

so:

$m_{Jo} = 195 \ kg - m_{Al}$ .

$m_{Al} \ v_{Al_f} + (195 \ kg - m_{Al}) \ v_{Jo_f} = 0$

$m_{Al} \ v_{Al_f} - m_{Al} \ v_{Jo_f}= - 195 \ kg \ v_{Jo_f}$

$m_{Al} \ (v_{Al_f} - v_{Jo_f})= - 195 \ kg \ v_{Jo_f}$

$m_{Al} = \frac{ - 195 \ kg \ v_{Jo_f} } { v_{Al_f} - v_{Jo_f} }$

$m_{Al} = \frac{195 \ kg \ v_{Jo_f} } { v_{Jo_f} - v_{Al_f} }$

Now, we can use the values:

$v_{Al_f}= 10.2 \frac{m}{s}$

$v_{Jo_f}= - 11.4 \frac{m}{s}$

where the minus sign appears as they are moving at opposite directions

$m_{Al} = \frac{195 \ kg ( - 11.4 \frac{m}{s} ) } { (- 11.4 \frac{m}{s}) - 10.2 \frac{m}{s} }$

$m_{Al} = 102.92 \ kg$

and this is the Al's mass.

5 0

2 years ago

What is the relationship between temperature and height in the troposphere ,stratosphere,mesophere,thermosphere,exosphere

Soloha48 [4]

In general the higher we go the cooler it becomes . temperature fall continues within the lowermost layer of our atmosphere, known as the troposphere. Above the troposphere, the stratosphere exists and in this region the temperature increases with an increase in altitude. The mesosphere is the part of the atmosphere that lies above the stratosphere. In this region, the temperature falls with an increase in altitude. And finally as we continue rising up, we reach the thermosphere, where the temperature increases with increased altitude.

3 0

3 years ago

Use the following d/t graph to determine the velocity of the object

marin [14]

Answer:

1/3 m/s

Explanation:

Because the graph goes from 3 to 8 on the Y axis we know that each line is 0.5 and on the X axis each line is 1, Then, the slope , or velocity, is 1/3

see? This graph is kinda set up to throw you.

Is there a 1/3 option for this ??

5 0

1 year ago

What is the best matral or mechaniazime to use in a egg drop form 30 feet

DiKsa [7]

Answer:

Ok so there are many ways to go at this.

you can get a zip lock bag and put a bunch of plastic around the egg inside the bag. (image down below)

Just anything to slow down the descent speed.

Cushion the egg so that something other than the egg itself absorbs the impact of landing.

Explanation:

8 0

1 year ago