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kakasveta [241]
3 years ago
15

What does Newton’s law of universal gravitation say about the distance between objects?

Physics
1 answer:
SashulF [63]3 years ago
3 0
Newton law of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
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A magic medallion is suspended from a string inside a compartment of Hogwarts Express which is running straight westwards on hor
Serggg [28]

Answer:

a = 1 m/s²  and

Explanation:

The first two parts can be seen in attachment

We use Newton's second law on each axis

Y axis

      Ty - W = 0        

      Ty = w

X axis

     Tx = m a

With trigonometry we find the components of tension

    Sin θ = Ty / T

    Ty = T sin θ

    Cos θ = Tx / T

    Tx = T cos θ

We calculate the acceleration with kinematics

   Vf = Vo + a t

   a = (Vf -Vo) / t

   a = (20 -10) / 10

   a = 1 m/s²

We substitute in Newton's equations

     

  T Sin θ = mg

  T cos θ = ma

We divide the two equations

  Tan θ = g / a

  θ = tan⁻¹ (g / a)

  θ = tan⁻¹ (9.8 / 1)

  θ = 84º

We see that in the expression of the angle the mass does not appear therefore you should not change the angle

4 0
3 years ago
What is not changed when work is done by a machine?
Irina18 [472]
B) The amount of work done
8 0
3 years ago
Read 2 more answers
What happened to an iron bar if it is heated from 32 degree Celsius to 64 degree Celsius
olganol [36]

Answer:

it got hotter

Explanation:

it just did

5 0
3 years ago
Before starting this problem, review Conceptual Example 3 in your text. Suppose that the hail described there comes straight dow
bulgar [2K]

Answer:

0.9 N

Explanation:

The force exerted on an object is related to its change in momentum by:

F=\frac{\Delta p}{\Delta t}

where

F is the force exerted

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be rewritten as

\Delta p = m(v-u)

where

m is the mass

u is the initial velocity

v is the final velocity

So the formula can be rewritten as

F=\frac{m(v-u)}{\Delta t}

In this problem we have:

\frac{m}{\Delta t}=0.030 kg/s is the mass rate

u=-15 m/s is the initial velocity

v=+15 m/s is the final velocity

Therefore, the force exerted by the hail on the roof is:

F=(0.030)(+15-(-15))=0.9 N

6 0
3 years ago
I need help quickly pls
sukhopar [10]

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

4 0
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