The term that best described a 10 gram of KClO3 per 100 grams of water solution at 30 degree Celcius is Saturated. The solubility chart is needed for this work. If the solubility chart is drawn for KClO3, it will be observed that the proportion of KClO3 that is needed to dissolve in 100ml of water to make the solution saturated is 10 grams at 30 degree Celcius.
The reaction between with calcium chloride can be shown as-+→↓+2mCl. The molecular weight of is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of = (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 moles to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989× moles of calcium sulfate.
Thus, 9.989× moles of reacts in this reaction.
Let assume the atomic mass of m is x thus the molecular weight of is 2x+96.
So we may write 9.989×× (2x+96) =1.42
Or, 2x + 96 = 142.146
Or, 2x = 46.146
Or, x = 23.073
Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).