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Usimov [2.4K]
3 years ago
15

A student uses 0.0821 L• atm/mol • K as the value of the gas constant. What is most likely true about the variables in the ideal

gas law?
P has the units of liters • atmospheres, and T has the units of kelvin.
P has the units of liters • atmospheres, and T has the units of degrees Celsius.
V has the units of liters, and T has the units of kelvin.
V has the units of liters, and T has the units of degrees Celsius.
Chemistry
2 answers:
yulyashka [42]3 years ago
6 0

Answer: V has the units of liters, and T has the units of kelvin.

Ideal gas law: p·V = n·R·T.  

atm · L = mol · L·atm/mol·K · K; both side of equatation have same values.

R = 0,08206 L·atm/mol·K; universal gas constant.  

p is pressure of the gas, unit is standard atmosphere (atm).

V is volume of the gas, unit is liters (L).

n is amount of substance of the gas; unit is mole (mol).

T is temperature of the gas, unit is Kelvin (K

Hope this helps!!

Explanation:

Bingel [31]3 years ago
6 0

Answer: V has the units of liters, and T has the units of kelvin.

Explanation:

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creativ13 [48]

Answer:

Too high a value

Explanation:

HA + NaOH ⟶ NaA +H₂O

If the student has gone slightly past the equivalence point, they have added too much base.

The moles of HA are directly proportional to the moles of NaOH, so the moles of acid that the student calculates will be too high.

The calculated concentration of acid will also be too high.

4 0
4 years ago
A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
andrew-mc [135]

Answer: The molecular formula for the given organic compound X is C_6H_{8}O_7

Explanation:

We are given:

Mass of CO_2=4.13g

Mass of H_2O=1.13g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, =\frac{12}{44}\times 4.13=1.13g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, \frac{2}{18}\times 1.13=0.125g of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles

Moles of Hydrogen =\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles

Moles of Oxygen =\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = \frac{0.094}{0.094}=1

For Hydrogen = \frac{0.125}{0.094}=1.33

For Oxygen = \frac{0.109}{0.094}=1.16

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is C_6H_8O_7

Empirical mass = 6\times 12+8\times 1+7\times 16=192g

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

Putting values in above equation, we get:

n=\frac{192g/mol}{192g/mol}=1

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_6H_8O_7\times 1=C_6H_{8}O_7

Thus molecular formula for the given organic compound X is C_6H_{8}O_7

7 0
3 years ago
Calculate no of moles in 42g of carbon ?
kondaur [170]

Answer:

\huge\boxed{n = 3.5\ moles}

Explanation:

<u><em>Given :</em></u>

Mass in grams = m = 42 g

Molar Mass = M = 12

<u><em>Required:</em></u>

No. of moles = n = ?

<u><em>Formula :</em></u>

m = m / M

<u><em>Solution:</em></u>

n = 42 / 12

n = 3.5 moles

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