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love history [14]
3 years ago
8

Dear Sir/ Ma'am,

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

$150

Step-by-step explanation:

Let n = the number of students and

Let x = the contribution per student.

We have two conditions:

(1)  12 900 = nx

(2) 12 900 = (n+14)(x - 21)

Set (1) = (2)                                   nx = (n+14)(x - 21)

Remove parentheses:                nx = nx - 21n + 14 x - 294

Subtract nx from each side         0 = -21n + 14x  - 294

Divide each side by -7            (3) 0 =     3n   -    2x +  42  

Divide each side of (1) by x     (4) n = 12 900/x

Substitute (4) into (3)                    0 = (3 × 12 900)/x - 2x + 42

                                                      0 = 38 700/x - 2x  + 42

Multiply each side by x                0 = 38 700     - 2x² + 42x

Multiply each side by -1                0 =  2x² - 42x - 38 700

Solve the quadratic equation  

x = [-b±√(b² - 4ac)]/(2a)

x = {42 ± √[(42² - 4×2(-38700)]}/(2 × 2)

  = [42 ± √(1764 +309 600]/4

  = [42 ± √(311 364)]/4

  = (42 ± 558)/4

  = 600/4

  = 150

Each student contributes $150.

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Semmy [17]

Answer:

see attachment for graph

Step-by-step explanation:

< or > : dashed line

≤ or ≥ : solid line

< or ≤ : shade below the line

> or ≥ : shade above the line

<u>To graph the line y < 3x-2</u>

Rewrite the equation as: y = 3x - 2

Find two points on the line:

when x = 0,  y = 3(0) - 2 = -2  →  (0, -2)

when x = 3,  y = 3(3) - 2 = 7  →  (3, 7)

Plots the found points (0, -2) and (3, 7).

Draw a straight, dashed line through the points.

<u>To graph the line y ≥ -x + 3</u>

Rewrite the equation as: y = -x + 3

Find two points on the line:

when x = 0,  y = -(0) + 3 = 3  →  (0, 3)

when x = 3,  y = -(3) + 3 = 0  →  (3, 0)

Plots the found points (0, 3) and (3, 0).

Draw a straight, solid line through the points.

Shade above the solid line and below the dashed line to the right of where the two lines intersect.  <u>The shaded area is the area of all possible solutions</u>.

5 0
2 years ago
Read 2 more answers
a mixture of peanuts and corn sells for P40 per kilo. The peanuts sell for P42 per kilo while the corn sells for P36 per kilo. h
Lelu [443]

Answer:

The weight of peanuts in the mixture   = 8  kg

The weight of corns in the given mixture = 4 kg

Step-by-step explanation:

Let us assume the weight of peanuts in the mixture   = x kg

The weight if corns in the given mixture = y kg

Total weight = (x + y) kg

The combined mixture weight = 12 kg

⇒ x  + y = 12  ..... (1)

Cost of per kg if mixture  = $ 40

So, the cost of (x + y) kg mixture  = (x+y) 40 = 40(x+ y)   ..... (2)

 

The cost of 1 kg of peanuts =  $ 42

So cost of x kg of peanuts  = 42 (x)  = 42 x

The cost of 1 kg of corns  = $ 36

So cost of y kg of corns  = 36 (y)  = 36 y

So, the total cost of x kg peanuts  + y kg corns =  42 x +  36 y  .... (3)

From (1) and (2), we get:

40(x+ y)  = 42 x +  36 y

x +  y = 12 ⇒ y = 12 -x

Put this in  40(x+ y)  = 42 x +  36 y

We get:

40(x+ 12 -x)  = 42 x +  36 (12 -x)

480 = 42 x + 432 - 36 x

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or, x  = 8

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5 0
3 years ago
Solve for b
Alex73 [517]

Answer:

b=\sqrt{21}

Step-by-step explanation:

Considering the given figure the sides 'b' , '2' and '5' are making the sides of a right angled triangle in the top right corner of the square, where

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Using Pythagoras Theorem:

                (Hypotenuse)^2=(Perpendicular)^2+(Base)^2\\

       Implementing the values in the formula:

                      5^2= b^2+2^2

                     b^2=5^2-2^2\\\\b^2=25-4\\\\b^2=21\\\\b=\sqrt{21}

So, the value of 'b' is \sqrt{21} which is same for the the given 'b' in the figure.

                 

7 0
4 years ago
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Inessa [10]
The answer is 78,880
4 0
3 years ago
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Nonamiya [84]

Answer:

P(Y=0) = 0.1353

Step-by-step explanation:

From the question we are told that:

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Generally the equation for Exponential distribution is mathematically given by

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Therefore

Possion Y

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Generally the equation for  The probability that there are no major cracks in a 10 mile stretch of the highway is mathematically given by

 P(Y=0) = \frac{e-2 (2)0}{0!}

 P(Y=0) = e-2

 P(Y=0) = 0.1353

7 0
3 years ago
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