Answer:
Na ·
Explanation:
Hello!
In this case, since the Lewis dot structure of any element illustrates the number of valence electrons at the outer shell; we can set up the electron configuration of sodium to obtain:
We can see there is only one valence electron, for that reason the Lewis dot structure is:
Na ·
Whereas the dot represents the valence electron.
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You would know that the variable is quantitative if it shows any number to express the quantity. For example, quantitative variables are 50°C, 5 atm, 2 moles, 100 L and so on. A variable is qualitative if it expresses a relative quantity but not expressing a number. Examples would be: few, too hot, several, or even describing the characteristics of a variable. Hence, when the variable is in grams, then that would be quantitative.
Answer:
Substitution.
Explanation:
Claisen reaction was first published in 1887 by a prominent German chemist known as Rainer Ludwig Claisen.
A Claisen reaction is a nucleophilic substitution in which an enolate is the nucleophile. It's typically a reaction of two molecules of an ester to form a β-keto ester, in the presence of an alkoxide base. Thus, a Claisen reaction is simply a characteristic condensation reaction of esters through a nucleophilic carbonyl substitution with an enolate such as a ketone enolate or an ester enolate.
Furthermore, a Claisen reaction results in the formation of a carbon-carbon bond in the presence of a strong base to yield a β-keto ester.
Answer:
Explanation:
Hello,
In this case, for the computation of the energy loss when the cooling process is carried out, we use the shown below equation:
Whereas we need the mass, specific heat and change in temperature of iron within the process. Thus, the only value we need is the specific heat that is 0.444 J/(g°C), therefore, we compute the heat loss:
Negative sign points out the loss due to the cooling.
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Answer:
53% aluminium is present.
Explanation:
Given data:
Mass of aluminium in bauxite = 108 g
Total mass of sample = 204 g
Percentage of aluminium = ?
Solution:
Formula:
Percentage = Mass of aluminium / total mass of sample× 100
Now we will put the values in formula:
Percentage = 108 g/204 × 100
Percentage = 0.53 × 100
Percentage = 53%
So in given 204 g of bauxite there is 53% aluminium is present.
