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harina [27]
3 years ago
14

The image above shows a type of metamorphic rock called gneiss. Gneiss is characterized by alternating bands of light and dark m

inerals. The bands in this particular sample of gneiss have been folded.
The characteristics of this rock developed due to _____ and _____ during the rock's formation.
Chemistry
1 answer:
finlep [7]3 years ago
4 0

Answer: first blank is heating second blank is pressure i think but i know that its NOT freezing

Explanation:

I did it and got it right

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SOMEONE PLS HELP ITS FOR A TEST!!
Damm [24]

Explanation:

4=true

5. true

hope this helps. good luck with your test.

6 0
3 years ago
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Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at
aleksandr82 [10.1K]

Answer:

Explanation:

Melting and boiling point variations are not clear (do not have uniform pattern) in periodic table. But we can see, some elements have higher melting and boiling points and some have less. Here we study melting and boiling points of s, p, d blocks elements. IVAth group elements (C,Si) show high melting and boiling points because they have covalent gigantic lattice structures.

5 0
2 years ago
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Hydrophobic molecules (like oil) tend to self-associate in water rather than dissolve. What is the MAJOR energetic contribution
anyanavicka [17]

Answer: The MAJOR energetic contribution to this property is the self association that maximizes the entropy of the water molecules.

Explanation:

Hydrophobic molecules (like oil) tend to self-associate in water rather than dissolve in it. The MAJOR energetic contribution to this property is the self association of this oil which increases the degree of disorderliness of the water molecules.

4 0
2 years ago
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What minimum frequency of light is required to ionize boron?
Nadusha1986 [10]

Answer:

frequency  = 8.22 x 10¹⁴ s⁻¹

Explanation:

An electron's positional potential energy while in a given principle quantum energy level is given by Eₙ = - A/n² and A = constant = 2.18 x 10⁻¹⁸j. So to remove an electron from the valence level of Boron (₅B), energy need be added to promote the electron from n = 2 to n = ∞. That is, ΔE(ionization) = E(n=∞) - E(n=2) = (-A/(∞)²) - (-A/(2)²) = [2.18 x 10⁻¹⁸j/4] joules = 5.45 x 10⁻¹⁹ joules.

The frequency (f) of the wave ionization energy can then be determined from the expression ΔE(izn) = h·f; h = Planck's Constant = 6.63 x 10⁻³⁴j·s. That is:

ΔE(izn) = h·f => f = ΔE(izn)/h = 5.45 x 10⁻¹⁹ j/6.63 x 10⁻³⁴ j·s = 8.22 x 10¹⁴ s⁻¹

3 0
2 years ago
Which of the following is NOT an example of proxy data?
Tomtit [17]

Answer:

itz e

Explanation:

8 0
3 years ago
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