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Nikolay [14]
3 years ago
13

Assume the earth to be a nonrotating sphere with mass MEME and radius RERE. If an astronaut weights WW on the ground, what is hi

s weight when he is 2RE2RE above the surface of the earth
Physics
1 answer:
Solnce55 [7]3 years ago
6 0

Answer:

The weight at a distance 2 RE from surface of earth is <em>W/9</em>

Explanation:

For the value of acceleration due to gravity (g), we have a formula, that is:

g = (G)(ME)/(RE)²    ----- equation (1)

where,

G = Gravitational Constant

ME = Mass of Earth

RE = Radius of Earth

g = Acceleration due to gravity on surface of earth = 9.8 ms²

When the person goes 2RE, distance above earth's surface. Then the total distance from center of earth becomes: 2RE + RE = 3RE.

Therefore, equation (1) becomes:

gh = (G)(ME)/(3RE)²

where,

gh = acceleration due to gravity at height

gh = (G)(ME)/(RE)²9

using equation (1), we get:

gh = g/9

Now, he weight is given by formula:

W = mg   ------- equation (2)

At height 2RE

Wh = (m)(gh)

where,

Wh = Weight at height = ?

m = mass of astronaut

Therefore, using vale of gh, we get:

Wh = mg/9

Using equation (2), we get:

<u>Wh = W/9</u>

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Answer:

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Explanation:

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3 years ago
S Assume you have a battery of emf E and three identical lightbulbs, each having constant resistance R. What is the total power
slega [8]

The total power delivered by the battery if the lightbulbs are connected is 9V^2/R

<h3>Power of a battery</h3>

The formula for calculating the power of a battery is expressed according to the equation;

Power = v^2/RT

where

R is the total resistance

v is the voltage or emf

If there are 3 identical lightbulbs, each having constant resistance R, then;

1/RT = 1/R + 1/R + 1/R

1/RT = 3/R

RT = R/3

The voltage drop across each   lightbulbs will be the same for parallel connection, hence;

Power = 3V^2/(R/3)

Power = 9V^2/R

Hence the total power delivered by the battery if the lightbulbs are connected is 9V^2/R

Learn more on power here: brainly.com/question/24858512

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8 0
1 year ago
What is the energy per photon absorbed during the transition from n = 2 to n = 3 in the hydrogen atom?
adelina 88 [10]

Answer : The energy of one photon of hydrogen atom is, 3.03\times 10^{-19}J

Explanation :

First we have to calculate the wavelength of hydrogen atom.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 10973731.6 m⁻¹

n_f = Higher energy level = 3

n_i= Lower energy level = 2

Putting the values, in above equation, we get:

\frac{1}{\lambda}=(10973731.6)\left(\frac{1}{2^2}-\frac{1}{3^2} \right )

\lambda=6.56\times 10^{-7}m

Now we have to calculate the energy.

E=\frac{hc}{\lambda}

where,

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 6.56\times 10^{-7}m

Putting the values, in this formula, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{6.56\times 10^{-7}m}

E=3.03\times 10^{-19}J

Therefore, the energy of one photon of hydrogen atom is, 3.03\times 10^{-19}J

3 0
3 years ago
Which graph shows the relationship between temperature, X, and kinetic energy, Y?
strojnjashka [21]
Answer: see the graph attached (straight line, passing through the origin and positive slope).


Justification:

1) Kinetic energy and temperature are in direct proportion. That means:

i)  Being kinetic energy y and temperature x: y α x

ii) That implies: y = kx,where k is the constant of proportionality.

iii) The graph is a line that passes through the origin and has positive slope k (k = y / x).

2) The proportional relationship between kinetic energy (KE) and temperature (T) is shown by the Boltzman law, which states:

Average KE = [3 / 2] KT, where K is Boltzman's constant, whose graph is of the form shown in the figure attached.

5 0
3 years ago
Read 2 more answers
Emilio pushes a 100 kg freshman with 200 N of force. How much is the freshman accelerated?
ladessa [460]

Explanation:

F = MA

200 = 100 * A

A = 200/100

A = 2m/sec^2

<h3><em>hope </em><em>it </em><em>helps </em><em>you </em></h3>
8 0
3 years ago
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