A 2-kg bowling ball sits on top of a building that is 40 meters tall.

2 answers:

7 0

A 2-kg bowling ball sits on top of a building that is 40 meters tall possess gravitational potential energy. It is energy an object possesses because of its position in a gravitational field. We calculate as follows:

GPE = mgh = 2(9.8)(40) = 784 J

Dahasolnce [82]3 years ago

6 0

The bowling ball is at rest, so it only has gravitational potential energy.

Ug = mgy
Ug = (2)(9.8)(40) = 784 J

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Minchanka [31]

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Velocity vector and acceleration vector in a uniform circular motion are related as.

mr_godi [17]

They are related as $\bold{\underline {v}\,.\,\underline a }= \bold{0}$

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