Answer: 1.93 x 10^24 molecules
Explanation:
CH4 is the chemical formula for methane, the first member of the alkane family.
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 molecule
So, 1 mole of CH4 = 6.02 x 10^23 molecules
3.2 moles of CH4 = Z
To get the value of Z, cross multiply:
(Z x 1 mole) = (6.02 x 10^23 molecule x 3.2 moles)
Z•mole = 19.26 x 10^23 molecules•mole
Divide both sides by 1 mole
Z•mole / 1 mole = 19.26 x 10^23 molecules•mole/ 1mole
Z = 19.26 x 10^23 molecules
Place Z in standard form
Z = 1.93 x 10^24 molecules
Thus, 3.2 moles of ch4 has 1.93 x 10^24 molecules
ANs:
[A] = [B] = 0.094 M
The following reaction was monitored as a function of time:
AB --> A + B
A plot of 1/[AB] versus time is a straight line with slope, K = 5.5×10^−2 M * s.
Now,
![\frac{1}{[AB]} = \frac{1}{[AB_{0} ]} + kT \\ \\ \frac{1}{[AB]} = \frac{1}{0.210} + (5.5* 10^{-2})*70 sec \\ \\ \\ \[AB] = 0.116](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5BAB%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BAB_%7B0%7D%20%5D%7D%20%2B%20kT%20%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B%5BAB%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B0.210%7D%20%2B%20%285.5%2A%2010%5E%7B-2%7D%29%2A70%20sec%20%5C%5C%20%5C%5C%20%5C%5C%20%5C%5BAB%5D%20%3D%200.116)
<span>Now, Since at 70 s, [AB] = 0.116 M,
then amount of AB lost: </span>
<span>0.210 M - 0.116 M = 0.094 M
</span>
Now, according to the stoichiometry of the reaction,
<span>AB : A : B = 1 : 1 : 1,
</span>
<span>so both [A] and [B] gained the same number of moles and thus have same concentration, as [AB] lost.
So, [A] = [B] = 0.094 M after 70 s.</span>
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