Compared to an atom of hydrogen in the ground state, an atom of hydrogen in the excited state has

__________ is a condition in which water droplets in air do not freeze even when the air cools below the freezing point.

IrinaK [193]

The answer is: supersaturation

7 0

3 years ago

15A.4(a) What is the temperature of a two-level system of energy separation equivalent to 400 cm−1 when the population of the up

maksim [4K]

Answer:

T = 525K

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

$\frac{N_{i}}{N} = e^{-\Delta E/kT}$ (1)

where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system

The energy between the two levels (ΔE) is:

$\Delta E = hck$

where h: is the Planck constant, c: is the speed of light and k: is the wavenumber

$\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J$

Solving the equation (1) for T:

$T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}$

With Ni = N/3 and k = 1.38x10⁻²³ J/K, the temperature of the two-level system is:

$T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K$

I hope it helps you!

3 0

3 years ago

Temperature depends on the average kinetic energy of athe particles in a sample how does this help with explaining why a plasma

Kryger [21]

Most particles in the plasma are heavy and slow and this statement explains why a plasma based light does not have a high temperature. The correct option among all the options that are given in the question is the third option. It is a fact that a heavy nuclei always takes more time to reach a thermal equilibrium.

4 0

3 years ago

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When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction:

slamgirl [31]

Answer:

1.5 mole

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

2Al(s) + 3Cl2(g) --> 2AlCl3(s)

Step 2:

Determination of the masses of Al and Cl2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of Al = 27g/mol

Mass of Al from the balanced equation = 2 x 27 = 54g

Molar Mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 from the balanced equation = 3 x 71 = 213g

From the balanced equation,

54g of Al reacted.

213g of Cl2 reacted

Step 3:

Determination of the limiting reactant.

This is illustrated below:

From the balanced equation above,

54g of Al reacted with 213g of Cl2.

Therefore, 40.5g of Al will react with = (40.5 x 213)/54 = 159.75g of Cl2.

From the calculations made above, there are leftover of Cl2 as 159.75g reacted out of 212.7g. Therefore, Cl2 is the excess reactant and Al is the limiting reactant.

Step 4:

Determination of the number of mole in 40.5g of Al. This is illustrated below:

Molar Mass of Al = 27g/mol

Mass of Al = 40.5g

Number of mole of Al =?

Number of mole = Mass/Molar Mass

Number of mole of Al = 40.5/27

Number of mole of Al = 1.5 mole

Step 5:

Determination of the number of mole of AlCl3 produced When 40.5 g of Al and 212.7 g of Cl2 combine together. This is illustrated below:

2Al(s) + 3Cl2(g) --> 2AlCl3(s)

From the balanced equation above,

2 moles of Al produced 2 moles of AlCl3.

Therefore, 1.5 mole of Al will also produce 1.5 mole of AlCl3.

From the calculations made above, 1.5 mole of AlCl3 is produced When 40.5 g of Al and 212.7 g of Cl2 combine together.

8 0

3 years ago

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What is the 3 step in the water cycle

Elodia [21]

Answer:

3 steps are

evaporation

condensation

precipitation

4 0

3 years ago

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