Answer:- 
Explanations:- It's a double replacement reaction where a precipitate of silver(I)bromide is formed. A dpuble replacement reaction in general looks as AB + CD \rightarrow AD + CB
To balance the equation we need to multiply gold compounds on both sides by 2 and the balanced equation is..

Answer:
The new temperature is 373 K
Explanation:
Step 1: Data given
Volume air = 5000 mL = 5.0 L
Temperature = 223K
New volume = 8.36 L
Step 2: Calculate the new temperature
V1/T1 = V2/T2
⇒V1 = the initial volume = 5.0 L
⇒T1 = the initial temperature = 223 K
⇒V2 = the new volume = 8.36 L
⇒T2 = the new temperature
5.0/223 = 8.36 /T2
T2 = 373 K
The new temperature is 373 K
Oxidation of D -Ribose in presence of hypobromous acid gives D-Ribonic acid
Answer:
The equation to show the the correct form to show the standard molar enthalpy of formation:

Explanation:
The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.
Given, that 1 mole of
gas and 1 mole of
liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

Divide the equation by 2.

The equation to show the the correct form to show the standard molar enthalpy of formation:

Answer:
Explanation:cool thre answer is 009000000000.1 because you have to add them so ye