Water flow will be reduced in a pipe if the pipe is constricted. True False

Intelligence tests that are given to participants in groups

White raven [17]

a. are typically paper-and-pencil measures.

Similar with psychological tests, mostly structured personality tests.

Psychological tests comes two ways: 
The structure psychological tests or, objectives tests and unstructured psychological tests or, also called projective tests. By what you are referring the responder strongly asserts a projective tests which in definition comes with an unambiguous stimuli or no paper test just drawings and images. If what the responder’s suggesting is correct you are referring to the Rorschach projective tests, these tests are a figure symmetrically placed in an inkblot that lets you visualize or create a mental picture out of it, and makes you describe what you in see much detail as you can.

4 0

3 years ago

A 1.25 x 10-4 C charge is moving5200 m/s at 37.0° to a magnetic fieldof 8.49 x 10-4 T. What is the magneticforce on the charge?

juin [17]

0.0003321 Newtons

Explanation

We are given the charge, its velocity, and the magnetic field strength and direction. We can thus use the equation to find the force

$\begin{gathered} F=qvBsinθ \\ where\text{ F is the magnetic force} \\ q\text{ is the charge} \\ v\text{ is the velocity of the charge} \\ Bis\text{ the magnetic field} \\ \theta\text{ is the angle} \end{gathered}$

so

Step 1

Let

$\begin{gathered} q=1.25*10^{-4\text{ }}C \\ v=5200\frac{m}{s} \\ \theta=37\text{ \degree} \\ B=8.49*10^{-4}T \end{gathered}$

now, replace

$\begin{gathered} F=qvBs\imaginaryI n\theta \\ F=1.25*10^{-4}\text{ C*5200 }\frac{m}{s}*8.49*10^{-4}Tsin(37) \\ F=0.0003321\text{ Newtons} \\ \end{gathered}$

so, the answer is

0.0003321 Newtons

I hope this helps you

7 0

1 year ago

Ohm's law relates the current, voltage, and resistance in a circuit. Use Ohm's law to determine what will happen to the remainin

krek1111 [17]

Answer:

R = ½ R₀

Explanation:

This is an exercise in Ohm's law,

V = IR

in the initial case

V₀ = I₀ R₀ (1)

indicates that the voltage remains constant and the current is doubled

I = 2 I₀

V₀ = I R

we substitute

V₀ = 2 I₀ R

R = ½ V₀ / I₀

we replace by equation 1

R = ½ R₀

8 0

4 years ago

A copper ornament has a mass of 0.0693 Kg and changes from a temperature of 18 degrees celcius to 26 degrees Celsius. How much h

zhuklara [117]

Answer: 216.2 J

Explanation: The heat energy of copper is the expressed in Q=mc∆T. First make sure that the mass 0.0693 kg is converted into grams to cancel both units.

Q= 69.3 g x 390 J/g°C x 26 °C-18°C = 216.2J

5 0

4 years ago

Read 2 more answers

miniature spring-loaded, radio-controlled gun is mounted on an air puck. The gun's bullet has a mass of 5.00 g, and the gun and

Tamiku [17]

Answer:

12 m/s

Explanation:

From the question,

Applying the law of conservation of momentum,

total momentum before collision = Total momentum after collision

mu+Mu' = mv+Mv'........................... Equation 1

Where m = mass of the bullet, u = initial velocity of the bullet, M = combined mass of the gun and the puck, u' = initial velocity of the gun and the puck, v = final velocity of the bullet, v' = final velocity of the gun and the puck

make v the subeject of the equation

v = [(mu+Mu')-Mv']/m................. Equation 2

Given: m = 5.00 g = 0.005 kg, M = 120 g = 0.12 kg, u = u' = 0 m/s (at rest), v' = 0.5 m/s

Substitute these values into equation 2

v = [0-(0.12×0.5)]/0.005

v = -0.06/0.005

v = -12 m/s

The negative sign can be ignored since we are looking for the speed, which has only magnitude.

Hence the speed of the bullet is 12 m/s

5 0

3 years ago