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Lana71 [14]
3 years ago
8

Water flow will be reduced in a pipe if the pipe is constricted. True False

Physics
1 answer:
Alexeev081 [22]3 years ago
5 0

The CORRECT answer is TRUE.

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A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box
vodka [1.7K]
The formula for Force is F = MA, or Force is equivalent to the product of Mass and Acceleration. 

F = 128N.
M = 35.2kg.

128 = 35.2A
Divide both sides by 35.2 to solve for the acceleration.
A = ~3.636

The acceleration is 3.636 m/s^2.

I hope this helps!
4 0
3 years ago
Read 2 more answers
A ball with a mass of 5000 g is floating on the surface of a pool of water.
Vitek1552 [10]

Answer:

d

Explanation:

reply the the question

8 0
3 years ago
Sound with frequency 1300 Hz leaves a room through a doorway with a width of 1.03 m . At what minimum angle relative to the cent
AlexFokin [52]

Answer:

  about 14.7°

Explanation:

The formula for the angle of the first minimum is ...

  sin(θ) = λ/a

where θ is the angle relative to the door centerline, λ is the wavelength of the sound, and "a" is the width of the door.

The wavelength of the sound is the speed of sound divided by the frequency:

  λ = (340 m/s)/(1300 Hz) ≈ 0.261538 m

Then the angle of interest is ...

  θ = arcsin(0.261538/1.03) ≈ 14.7°

At an angle of about 14.7°, someone outside the room will hear no sound.

6 0
3 years ago
If the frequency of a given wave increases,what happens to the wavelength?
Greeley [361]
It shortens so that the tips reach faster
8 0
3 years ago
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Weak magnetic fields can be measured at the surface of the brain. Although the currents causing these fields are quite complicat
STALIN [3.7K]

To develop this problem it is necessary to apply the concepts related to a magnetic field in spheres.

By definition we know that the magnetic field in a sphere can be described as

B = \frac{\mu_0}{2}\frac{Ia^2}{(z^2+a^2)^{3/2}}

Where,

a = Radius

z = Distance to the magnetic field

I = Current

\mu_0 = Permeability constant in free space

Our values are given as

D=2a = 16cm \rightarrow diameter of the sphere then,

a = 0.08m

Thus z = a

B = \frac{\mu_0}{2}\frac{Ia^2}{(a^2+a^2)^{3/2}}

B = \frac{\mu_0I}{2(2^{3/2})a}

B = \frac{\mu_0 I}{2^{5/2}a}

Re-arrange to find I,

I = \frac{2^{5/2}Ba}{\mu_0}

I = \frac{2^{5/2}(3*10^{-12})(8*10^{-2})}{4\pi*10^{-7}}

I = 1.08*10^{-6}A

Therefore the current at the pole of this sphere is 1.08*10^{-6}A

5 0
3 years ago
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