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2 years ago

HELP ME OUT PLEASE!!!!!

Physics

2 answers:

masya89 [10]2 years ago

7 0

Answer:

B and D is the correct answer.

Explanation:

Nataliya [291]2 years ago

3 0

Answer:

B and D is the answer

Explanation:

I took the assignment <3

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I have 2 bulbs one coverts 60% of energy to light 45% which is the most efficient and what happens to the rest of the energy

Leya [2.2K]

Answer:

The first one (60%)

Explanation:

The first one converts 15% more energy than the other one. Therefore, it is more efficient.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Two speakers, one directly behind the other, are each generating a 240-Hz sound wave. What is the smallest separation distance b

AveGali [126]

Answer:

The smallest separation distance between the speakers is 0.71 m.

Explanation:

Given that,

Two speakers, one directly behind the other, are each generating a 240-Hz sound wave, f = 240 Hz

Let the speed of sound is 343 m/s in air. The speed of sound is given by the formula as :

$v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343\ m/s}{240\ Hz}\\\\\lambda=1.42\ m$

To produce destructive interference at a listener standing in front of them,

$d=\dfrac{\lambda}{2}\\\\d=\dfrac{1.42}{2}\\\\d=0.71\ m$

So, the smallest separation distance between the speakers is 0.71 m. Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

Which organism would most likely have new gene combinations?

ella [17]

Answer:

a hamster resulting from sexual reproduction

4 0

2 years ago

Assignment 10 Coulombic Equation Practice Directions: Complete the following problems to calculate the electrostatic force that

Tatiana [17]

Answer:

Magnitude of the force between the charges is F = 1.92×10^20N

Explanation:

Given the magnitude of force according to coulombs law

F =K[(q1*q2)/r2]

Where q1 and q2 are the charges

r is the distance between the charges

K is the coulombs constant

Substituting the given values, we have;

F = 8.98×10^9 × 1.5×10^6 × 3.2×10^4/1.5²

F = 43.1×10^19/2.25

F = 19.16×10^19N

F = 1.92×10^20N

8 0

3 years ago

A particle starts from the origin at t = 0 with an initial velocity of 4.8 m/s along the positive x axis.If the acceleration is

tia_tia [17]

Answer:

Part a)

Velocity = 6.9 m/s

Part b)

Position = (3.6 m, 5.175 m)

Explanation:

Initial position of the particle is ORIGIN

also it initial speed is along +X direction given as

$v_x = 4.8 m/s$

now the acceleration is given as

$\vec a = -3.2 \hat i + 4.6 \hat j$

when particle reaches to its maximum x coordinate then its velocity in x direction will become zero

so we will have

$v_f = v_i + at$

$0 = 4.8 - 3.2 t$

$t = 1.5 s$

Part a)

the velocity of the particle at this moment in Y direction is given as

$v_f_y = v_i + at$

$v_f_y = 0 + 4.6(1.5)$

$v_f_y = 6.9 m/s$

Part b)

X coordinate of the particle at this time

$x = v_x t + \frac{1}{2}a_x t^2$

$x = 4.8(1.5) - \frac{1}{2}(3.2)(1.5^2)$

$x = 3.6 m$

Y coordinate of the particle at this time

$y = v_y t + \frac{1}{2}a_y t^2$

$y = 0(1.5) + \frac{1}{2}(4.6)(1.5^2)$

$y = +5.175 m$

so position is given as (3.6 m, 5.175 m)

5 0

3 years ago