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goldenfox [79]
3 years ago
6

A woman is standing in the ocean, and she notices that after

Physics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

Period, T = 10.86 seconds  

Frequency, f = 0.092 Hz  

Wavelength, \lambda=39.257883151578\ m          

Speed, v = 3.61 m/s                                                        

Explanation:

It is given that,

A woman notices that a wave crest passes by, five more crests pass in a time of 54.0 .

The distance between two successive crests is, the wavelength of wave, \lambda=39.257883151578\ m

(b)Frequency of a wave is given by number of oscillations per second such that,

f=\dfrac{n}{t}

f=\dfrac{5}{54}

f = 0.092 Hz

(a) Let T is the period of the wave. It is inverse of frequency of a wave such that,

T=\dfrac{1}{f}

T=\dfrac{1}{0.092}

T = 10.86 seconds

(c) The distance between two successive crest or trough is called wavelength of a wave, \lambda=39.257883151578\ m.

(d) The speed of a wave is given by :

v=f\lambda

v=0.092\times 39.257883151578

v = 3.61 m/s

Hence, this is the required solution.

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A rope is tied to a box and used to pull the box 2.3 m along a horizontal floor. The rope makes an angle of 30∘ with the horizon
Savatey [412]

Answer:

Answered

Explanation:

A) The work done by gravity is zero because displacement and the gravitational force are perpendicular to each other.

W= FS cosθ

θ= 90 ⇒cos90 = 0 ⇒W= 0

B) work done by tension

W= Tcosθ×S= 5cos30×2.30= 10J

C) Work done by friction force

W= f×s=1×2.30= 2.30 J

D) Work done by normal force is Zero because the displacement and the normal force are perpendicular to each other.

E) The net work done= Work done by tension in the rope - frictional work

=10-2.30= 7.7 J

6 0
2 years ago
The human ear canal is about 2.8 cm long. If it is regarded as a tube that is open at one end and closed at the eardrum, what is
Diano4ka-milaya [45]

Answer:

f = 3.1 kHz

Explanation:

given,

length of human canal =2.8 cm = 0.028 m

speed of sound = 343 m/s

fundamental frequency  = ?

The fundamental frequency of a tube with one open end and one closed end is,

f = \dfrac{v}{4L}

f = \dfrac{343}{4\times 0.028}

f = \dfrac{343}{0.112}

       f = 3062.5 Hz

       f = 3.1 kHz

hence, the fundamental frequency is equal to f = 3.1 kHz

8 0
2 years ago
Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak
ANTONII [103]

Answer:

(a) 8Ω (b)  Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can  two 8-Ω speakers be  arranged, when one =  4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is  = (16 x 16)/(16 + 16) = 8 ohm

(b) compare  your arrangement  power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

8 0
3 years ago
Einstein's theory of relativity is currently the best explanation of gravity. What is likely to happen to this theory in the fut
Trava [24]
I believe the answer is C
8 0
3 years ago
Read 2 more answers
A 438kg car is accelerating east at 2.55m/s^2. What is the total force acting east on the car
lisabon 2012 [21]

Answer:

<h2>1116.9 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 438 × 2.55

We have the final answer as

<h3>1116.9 N</h3>

Hope this helps you

5 0
3 years ago
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