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goldenfox [79]
3 years ago
6

A woman is standing in the ocean, and she notices that after

Physics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

Period, T = 10.86 seconds  

Frequency, f = 0.092 Hz  

Wavelength, \lambda=39.257883151578\ m          

Speed, v = 3.61 m/s                                                        

Explanation:

It is given that,

A woman notices that a wave crest passes by, five more crests pass in a time of 54.0 .

The distance between two successive crests is, the wavelength of wave, \lambda=39.257883151578\ m

(b)Frequency of a wave is given by number of oscillations per second such that,

f=\dfrac{n}{t}

f=\dfrac{5}{54}

f = 0.092 Hz

(a) Let T is the period of the wave. It is inverse of frequency of a wave such that,

T=\dfrac{1}{f}

T=\dfrac{1}{0.092}

T = 10.86 seconds

(c) The distance between two successive crest or trough is called wavelength of a wave, \lambda=39.257883151578\ m.

(d) The speed of a wave is given by :

v=f\lambda

v=0.092\times 39.257883151578

v = 3.61 m/s

Hence, this is the required solution.

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A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in
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The average power is 3.0\cdot 10^6 W

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where :

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

m = 2000 kg is the mass of the car

v = 60 m/s is the final speed of the car

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

u = 30 m/s is initial speed of the car

Soolving:

W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J

Now we can find the power required for the acceleration, which is given by

P=\frac{W}{t}

where

t = 9 s is the time elapsed

Solving:

P=\frac{2.7\cdot 10^6}{9}=3.0\cdot 10^6 W

Learn more about power:

brainly.com/question/7956557

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The energy levels of a particular quantum object are -11.7 eV, -4.2 eV, and -3.3 eV. If a collection of these objects is bombard
gogolik [260]

To solve this problem it is necessary to apply an energy balance equation in each of the states to assess what their respective relationship is.

By definition the energy balance is simply given by the change between the two states:

|\Delta E_{ij}| = |E_i-E_j|

Our states are given by

E_1 = -11.7eV

E_2 = -4.2eV

E_3 = -3.3eV

In this way the energy balance for the states would be given by,

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Therefore the states of energy would be

Lowest : 0.9eV

Middle :7.5eV

Highest: 8.4eV

8 0
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