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igomit [66]
3 years ago
6

A wire 50 cm long with an east-west orientation carries a current of 7.0 A eastward. There is a uniform magnetic field perpendic

ular to this wire. If the force on the wire is 0.5 N upward, what are the direction and magnitude of the magnetic field?
Physics
2 answers:
Gnoma [55]3 years ago
6 0

Answer:

North, 0.1428 Tesla

Explanation:

As we know that the magnetic force in the wire can be calculated as,

F=Bilsin(\Theta ).

Here the uniform magnetic field is perpendicular to wire than theta will be 90°.

So the magnetic force will become,

F=Bil.

Substitute 50 cm for l, 7 A for i, and 0.5 N for F in the above equation.

B=\frac{0.5}{50\times 1`0^{-2} m(7 A) }\\B=0.1428 T

Now according to Fleming's left hand law, if the current in the east ward direction and force is in upward direction then the value of magnetic field will be perpendicular to both in the north direction.

Therefore magnetic field will be 0.1428 T in the north direction.

konstantin123 [22]3 years ago
3 0

Answer:

The magnetic field is 0.143 T in north direction.

Explanation:

Given that,

Length = 50 cm

Current = 7.0 A

Force = 0.5 N

We need to calculate the magnetic field

Using formula of magnetic force

\vec{F}I\vec{L}\times\vec{B}

F=ILB

B=\dfrac{F}{IL}

B=\dfrac{0.5}{7.0\times50\times10^{-2}}

B=0.143\ T

The direction of the magnetic field toward north.

Hence, The magnetic field is 0.143 T in north direction.

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Ultraviolet light of wavelength 270 nm strikes a metal whose work function is 2.3 eV.What is the shortest de Broglie wavelength
soldier1979 [14.2K]

Answer:

The shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm

Explanation:

Given;

wavelength of ultraviolet light, λ = 270 nm

work function of the metal, φ = 2.3 eV = 2.3 x 1.602 x 10⁻¹⁹ J = 3.685 x 10⁻¹⁹ J

The energy of the ultraviolet light is given by;

E = \frac{hc}{\lambda}\\\\E = \frac{(6.626*10^{-34} )(3*10^{8}) }{270*10^{-9} }\\\\E = 7.362 * 10^{-19} \ J

The energy of the incident light is related to kinetic energy of the electron and work function of the metal by the following equation;

E = φ  + K.E

K.E = E - φ

K.E = (7.362 x 10⁻¹⁹ J) - (3.685 x 10⁻¹⁹ J )

K.E = 3.677 x 10⁻¹⁹ J

K.E = ¹/₂mv²

mv² = 2K.E

velocity of the electron is given by;

V = \sqrt{\frac{2K.E}{m} }\\\\V =  \sqrt{\frac{2(3.677*10^{-19}) }{9.1*10^{-31} } }\\\\V = 8.99*10^{5}  \ m/s

the shortest de Broglie wavelength for the electrons is given by;

\lambda = \frac{h}{mv}\\ \\\lambda = \frac{6.626*10^{-34} }{(9.1*10^{-31})( 8.99*10^{5} )}\\\\\lambda = 8.10*10^{-10} \ m\\\\\lambda = 0.81 \ nm

Therefore, the shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm

7 0
3 years ago
A refrigerator having a power rating of 350W operates for 12 hours a day. calculate the cost of electrical energy to operate it
rodikova [14]

Answer:

See the answers below.

Explanation:

The cost of energy can be calculated by multiplying each given value, a dimensional analysis must be taken into account in order to calculate the total value of the cost in Rs.

Cost=0.350[kW]*12[\frac{hr}{1day}]*30[days]*4.5[\frac{Rs}{kW*hr} ]=567[Rs]

The fuse can be calculated by knowing the amperage.

P=V*I

where:

P = power = 350 [W]

V = voltage = 240 [V]

I = amperage [amp]

Now clearing I from the equation above:

I=P/V\\I=350/240\\I=1.458[amp]

The fuse should be larger than the current of the circuit, i.e. about 2 [amp]

3 0
2 years ago
Two similar sized stones one heavy and one light dropped from the same height into a pond explain why the impact of the heavy st
Zigmanuir [339]
In energy point of view, the larger stone had more potential energy before dropping. impacting the water, the larger one, having more kinetic energy which changed from potential energy, tranfered energy to the water and formed wave. the amplitude of the wave indicate the energy of the wave. more energy more amplitude.
5 0
3 years ago
A distance of 2.00 mm separates two objects of equal mass. If the gravitational force between them is 0.0104 N, find the mass of
Reptile [31]
F = \frac{gm,m2}{r2}
r = 0.002

0.0104 = \frac{(6.673 x  10^{-11} }{ 0.002)^{2} }

m = 25.0kg
4 0
2 years ago
Read 2 more answers
An airplane is flying at a speed of 45 m/s when it drops a 40 kg food package to the Polar exploration team. If the plane drops
Alina [70]

To solve this problem we will apply the concepts related to energy conservation, so the potential energy in the package must be equivalent to its kinetic energy. From there we will find the speed of the package in the vertical component. The horizontal component is given, as it is the same as the one the plane is traveling to. Vectorially we will end up finding its magnitude. So,

PE = KE

mgh = \frac{1}{2}mv^2

Here,

m = Mass

g = Gravity

h = Height

v = Velocity

Rearranging to find the velocity

v = \sqrt{2gh}

Replacing,

v = \sqrt{2(9.8)(120)}

v = 48.49m/s

Using the vector properties the magnitude of the velocity vector would be given by,

|V| = \sqrt{v_x^2+v_y^2}

|V| = \sqrt{45^2+48.42^2}

|V| = 66.2m/s

Therefore the package is moving to 66.2m/s

3 0
3 years ago
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