Answer:
Chloroform= limiting reactant
0.209mol of CCl4 is formed
And 32.186g of CCl4 is formed
Explanation:
The equation of reaction
CHCl3 + Cl2= CCl4 + HCl
From the equation 1 mol of
CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4
From the question
25g of CHCl3 really with Cl2
Molar mass of CHCl3= 119.5
Molar mass of Cl2 = 71
Hence moles of CHCl3= 25/119.5 = 0.209mol
Moles of Cl2 = 25/71 = 0.352mol
Hence CHCl3 is the limiting reactant
Since 1 mole of CHCl3 gave 1mol of CCl4
It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4
Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g
Hey There!:
number of moles = 2 moles KI
Volume = 1 L
Therefore:
M = n /V
M = 2 / 1
M = 2.0 mol/L
hope this helps!
Answer:
Cellular respiration
Explanation:
Oxygen is required by the cell in the Krebs cycle as the ultimate proton acceptor (creating water an end product during making out ATPs). During the conversion of pyruvate from glycolysis to Acetyl-CoA that enters the Krebs cycle, the pyruvate is decarboxylated (or oxidized) hence creating carbon IV oxide as a byproduct.
Answer:
The diagram is attached.
Explanation:
Peptide just refers to two or more amino acids liking together. A dipeptide consists of two amino acids linking together. A polypeptide is more that two amino acids linking together.
