Answer:
See explanation
Explanation:
The substance under analysis must be a polar organic substance of high molecular mass. We must remember that as the magnitude of dispersion forces increases with increase in molecular mass, the melting point increases accordingly. Also polar organic substances have very high melting points due to the presence of polar bonds in the molecule..
Hence the intramolecular forces in the substance are covalent bonds while the intermolecular forces are both dispersion forces and dipole forces.
The substance may likely be 1,2,3,4,6,7,8-Heptachlorodibenzo-p-Dioxin which a white powder and melts at 264 °C.
Answer:The correct answer is ;
The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.
Explanation:
In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.
In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.
In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in 
molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent
In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in 
molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.
Answer:
HNO₃
Explanation:
Data given
Nitrogen = 9.8 g
Hydrogen = 0.70 g
Oxygen = 33.6 g
Empirical formula = ?
Solution:
Convert the masses to moles
For Nitrogen
Molar mass of N = 14 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 9.8 g/ 14 g/mol
no. of mole = 0.7
mole of N = 0.7 mol
For Hydrogen
Molar mass of H = 1 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 0.70 g/ 1 g/mol
no. of mole = 0.7
mole of H = 0.7 mol
For Oxygen
Molar mass of O = 16 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 33.6 g / 16 g/mol
no. of mole = 2.1
mole of O = 2.1 mol
Now we have values in moles as below
N = 0.7
H = 0.7
O = 2.1
Divide the all values on the smallest values to get whole number ratio
N = 0.7 / 0.7 = 1
H = 0.7 / 0.7 = 1
O = 2.1 / 0.7 = 3
So all have following values
N = 1
H = 1
O = 3
So the empirical formula will be HNO₃ i.e. all three atoms in simplest small ratio.
Atoms combine as the electrons from each atom are attracted to the nuclei of the atoms. The results in bonds ranging from 100%covalent to bonds with higher character. The combination of atoms to form compounds occurs when the compounds being formed are at lower energy than the original atoms. In chemical change, the molecules in the reactants interact to form new substances.
