Answer:
b. ΔH and ΔS are negative at all temperatures .
Explanation:
During the process of condensation ,
The gaseous state convert to liquid state ,
Hence , the entropy of the system reduces , i.e. , the randomness decreases .
And the value for entropy is negative ,
hence ,
Δ S = negative ,
Δ H = negative ,
Since ,
The heat is releasing from system .
hence , the most appropriate option will be ΔH and ΔS are negative at all temperatures .
MH₂ = 2×mH = 2×1g = 2 g/mol
Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol
Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.
W are given a chemical reaction:
To calculate the enthalpy change, we use the formula:
This is the amount of energy released when 0.1326 grams of sample was burned.
So, energy released when 1 gram of sample was burned is = 
Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:
Answer:
The answer is in the explanation.
Explanation:
The dissociation of a weak acid consist in the following equilibrium:
HX ⇄ H⁺ + X⁻
Where Ka is defined as:
Ka = [H⁺] [X⁻] / [HX]
A strong acid (HY) dissociates completely in water, thus:
HY → H⁺ + Y⁻
As the strong acid produces H⁺, in the equilibrium, the reaction shifts to the left -The undissociated form-, reducing the production of H⁺, allowing ignore the dissociation of the weak acid when calculating the pH.
