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statuscvo [17]
3 years ago
15

A math class has 7 girls and 3 boys in the seventh grade and 3 girls and 9 boys in the eighth grade. The teacher randomly select

s a seventh grader and an eighth grader from the class for a competition. What is the probability that the students she selects are both boys?
Write your answer as a fraction in simplest form.
Mathematics
1 answer:
Bumek [7]3 years ago
4 0

7th grade has 3 boy out of 10 students

 probability of picking a boy is 3/10

8th grade has 9 boys out of 12 students are boys

 probability of picking a boy is 9/12 reduced to 3/4

3/10 x 3/4 = 9/40 probability of picking 2 boys

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Solve the equation X³+2X²-5X -6​
Natali [406]

Answer: x = {-1, -3, 2}

<u>Step-by-step explanation:</u>

x³ + 2x² - 5x - 6 = 0

Use the rational root theorem to find the possible roots:  ±1, ±2, ±3, ±6

Use Long division, Synthetic division, or plug them into the equation to see which root(s) work <em>(result in a remainder of zero)</em>.

I will use Synthetic division.  Let's try x = 1

1 |  1    2    -5     -6

  |<u>  ↓    1      3     -2 </u>      

     1     3    -2    -8   ← remainder ≠ 0 so x = 1 is NOT a root

 Let's try x = -1

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      1     1     -6     0   ← remainder = 0 so x = -1 is a root!

The coefficients of the reduced polynomial are: 1, 1, -6  -->   x² + x - 6

Factor: x² + x - 6

          (x + 3)(x - 2)

Set those factors equal to zero to solve for x:

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3 years ago
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Answer:

(2,10) or x=2 y=10

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<em>1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.</em>

5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)

5x=2y-10 (Divide the 5 from the x)

x=2/5y-2

<em>2. Now take what you got for x and plug it into the x variable on the other equation.</em>

3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)

6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)

36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)

y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)

y=10

<em>3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.</em>

5x-2(10)=-10 (Multiple 2 by 10)

5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)

5x=10 ( Divide 10 by 5)

x= 2

<em>4. If needed, plug in the values of x and y to check your solution.</em>

Hope this could help! :)

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