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sergiy2304 [10]
3 years ago
8

What is a hypothesis

Physics
1 answer:
notsponge [240]3 years ago
7 0
A hypothesis can be described as an intelligent guess 
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What is the definition of erosion
babunello [35]

Answer:

Erosion is the process of eroding or being eroded by wind, water, or other natural agents.

Explanation:

"the problem of soil erosion"

the gradual destruction or diminution of something.

"the erosion of support for the party"

are examples of how it could be used.

5 0
3 years ago
Read 2 more answers
A toroid having a square cross section, 5.49 cm on a side, and an inner radius of 18.1 cm has 450 turns and carries a current of
joja [24]

Answer:

(a) 4.27 x 10^-4 Telsa

(b) 3.28 x 10^-4 Telsa

Explanation:

side of square, a = 5.49 cm

inner radius, r = 18.1 cm = 0.181 m

number of turns,N = 450

current, i = 0.859 A

(a)

The magnetic field due to a solenoid due to inner radius is

B = \frac{\mu_{0}Ni}{2\pi r_{inner}}

B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.181}

B = 4.27 x 10^-4 Telsa

(b)

The outer radius is R = 18.1 + 5.49 = 23.59 cm = 0.236 m

The magnetic field due to the outer radius is

B = \frac{\mu_{0}Ni}{2\pi r_{outer}}

B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.236}

B = 3.28 x 10^-4 Tesla

7 0
4 years ago
PE=?, m=.6kg, g=10m/s2, h=35m<br><br> PLS HELP I NEED THIS DONE
Karo-lina-s [1.5K]
210J

PE is mgh in this context.
7 0
4 years ago
*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude
kvv77 [185]

Answer:

Approximately 3.86\; {\rm N} (given that the magnitude of this charge is -7.35\; {\rm \mu C}.)

Explanation:

If a charge of magnitude q is placed in an electric field of magnitude E, the magnitude of the electrostatic force on that charge would be F = E\, q.

The magnitude of this charge is q = 7.35\; {\rm \mu C}. Apply the unit conversion 1\; {\rm \mu C} = 10^{-6}\; {\rm C}:

\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}.

An electric field of magnitude E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}} would exert on this charge a force with a magnitude of:

\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}.

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

4 0
2 years ago
In which of the following does personality psychology specialize?
ValentinkaMS [17]
B, Studying how ones' character changes over time... That's the only one that has to deal with personality. 
5 0
3 years ago
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