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dlinn [17]
3 years ago
11

PE=?, m=.6kg, g=10m/s2, h=35m PLS HELP I NEED THIS DONE

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0
210J

PE is mgh in this context.
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if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
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Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

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|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

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3 years ago
Average speed equals distance divided by time. on a journey to the
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The average speed will be 2.38×10⁶ m/sec.The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

<h3>What is the average speed?</h3>

The total distance traveled by an object divided by the total time taken is the average speed.

The speed calculated at any particular instant of time is known as the instantaneous speed.

Given data;

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The average speed is found as

\rm V_{avg}= \frac{d}{t} \\\\\ \rm V_{avg}= \frac{4.12 \times 10^{16}}{1.73 \times 10^{10} } \\\\\ V_{avg}=2.38 \times 10^6 \ m/sec

Hence, the average speed will be 2.38×10⁶ m/sec.

To learn more about the average speed, refer to the link;

brainly.com/question/12322912

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How does the orbital speed of an asteroid in a circular solar orbit with a radius of 4.0 AU compare to a circular solar orbit wi
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Answer:

The circular solar orbital speed at 4.0AU is 1/4( one fourth) that at 1.0AU

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