Answer:
#See solution for details.
Explanation:
1.
Tools:
.
:Calculate the speed of the wave using the time,
it takes to travel along the rope. Rope's length,
is measured using the meter stick.
-Attach one end of rope to a wall or post, shake from the unfixed end to generate a pulse. Measure the the time it takes for the pulse to reach the wall once it starts traveling using the stopwatch.
-Speed of the pulse can then be obtained as:

: Apply force of known value to the rope then use the following relation equation to find the speed of a pulse that travels on the rope.

-Use the measuring stick and measuring scale to determine
values of the rope then obtain
.
-Use the force measuring constant to determine
. These values can the be substituted in
to obtain 
Answer:
a) τ = 0.672 N m
, b) θ = 150 rad
, c) W = 100.8 J
Explanation:
a) for this part let's start by finding angular acceleration, when the angular velocity stops it is zero (w = 0)
w = w₀ + α t
α = -w₀ / t
α = 120 / 2.5
α = 48 rad / s²
The moment of inertia of a cylinder is
I = ½ M R²
Let's calculate the torque
τ = I α
τ = ½ M R² α
τ = ½ 2.8 0.1² 48
τ = 0.672 N m
b) we look for the angle by kinematics
θ = w₀ t + ½ α t2
θ = ½ α t²
θ = ½ 48 2.5²
θ = 150 rad
c) work in angular movement
W = τ θ
W = 0.672 150
W = 100.8 J
Answer: A. Object A will have a positive charge.
Explanation: If the number of protons and electrons are the same, their net charges cancel each other out, and you have a neutral charge. If electrons are transferred to another object, the amount of positive charge will outweigh the amount of negative charge. As a result, you are left with an overall positive charge in object A. Meanwhile, object B is now negative.
Missing figure in the problem: https://www.physicsforums.com/attachments/p4-46-gif.117834/
Solution:
part a) The bucket is not moving so the resultant of the forces acting on it is zero. Let's apply the equation of equilibrium. We have:

so

where T=90.5 N is the tension of the rope, and a factor 2 is applied because the string holds the bucket twice. From this we find

part b) Here the situation is different: the string holds the bucket only in one point. Moreover, the bucket is pulled up at constant velocity, so zero acceleration: this means that the resultant of the forces acting on the bucket is zero. Therefore, the equation of equilibrium in this case is

and so, since we know from part a) that

, we can find the new tension T: