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Sphinxa [80]
3 years ago
10

A rolling pin has two identical cylindrical handles attached to a larger handle that is 12 inches long. The large cylinder measu

res 5 inches in diameter and the handles measure 1.5 inches in diameter. What is the volume of the rolling pin in cubic inches? Round to the nearest tenth
Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

Volume of the rolling pin =  246.09 in^{3}  

Step-by-step explanation:

Length of larger cylinder L = 12 in

Diameter of larger cylinder D = 5 in

Diameter of two handles = 1.5 in

Length of two handles = 3 in

Volume of the rolling pin = Volume of two handles + Volume of larger cylinder

Volume of two handles = 2 (\pi r^{2}L)

Volume of two handles =  2 (3.14 × 0.75^{2} × 3 )

Volume of two handles = 10.59 in^{3}  

Volume of larger cylinder = (\pi r^{2}L)

Volume of larger cylinder = (3.14 × 2.5^{2} × 12 )

Volume of larger cylinder = 235.5 in^{3}  

Volume of the rolling pin =  10.59 + 235.5

Volume of the rolling pin =  246.09 in^{3}  

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Answer:

The value of k = 4/3

Step-by-step explanation:

* Lets explain how to solve the problem

- An equilateral triangle ABC is inscribed in a circle N

- The area of the triangle is √3

- The shaded area is the difference between the area of the circle

  and the area of the equilateral triangle ABC

- The shaded are = k π - √3

- We need to find the value of k

* <u><em>At first lets find the length of the side of the Δ ABC</em></u>

∵ Δ ABC is an equilateral triangle

∴ Its area = √3/4 s² , where s is the length of its sides

∵ The area of the triangle = √3

∴ √3/4 s² = √3

- divide both sides by √3

∴ 1/4 s² = 1

- Multiply both sides by 4

∴ s² = 4 ⇒ take √ for both sides

∴ s = 2

∴ The length of the side of the equilateral triangle is 2

* <u><em>Now lets find the radius of the circle</em></u>

- In the triangle whose vertices are A , B and N the center of the circle

∵ AN and BN are radii

∴ AN = BN = r , where r is the radius of the circle

∵ The sides of the equilateral angles divides the circle into 3 equal

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∵ The measure of the central angle in a circle equal the measure

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∵ ∠ANB is an central angle subtended by arc AB

∵ The measure of arc AB is 120°

∴ m∠ANB = 120°

- By using the cosine rule in Δ ANB

∵ AB = 2 , AN = BN = r , m∠ANB = 120°

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∴ 4=r^{2}+r^{2}+r^{2}

∴ 4=3r^{2}

- Divide both sides by 3

∴ r^{2}=\frac{4}{3}

- Take square root for both sides

∴ r = 2/√3

* <u><em>Lets find the value of k</em></u>

∵ Area circle = πr²

∵ r = 2/√3

∴ Area circle = π(2/√3)² = (4/3)π

∵ Area shaded = area circle - area triangle

∵ Area triangle = √3

∴ Area shaded = (4/3) π - √3

∵ Area of the shaded part is π k - √3

- Equate the two expressions

∴ π k - √3 = (4/3) π - √3

∴ k = 4/3

* The value of k = 4/3

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Step-by-step explanation:

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Rather than the 6th toss, there are 9 tosses. From these 9 tosses 1 toss can be selected in 9 ways.

Hence, the probability is 9\times\frac{1}{2^{10}} =  0.008789.

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