A. Horizontal component: 7.3 m/s
Explanation:
The horizontal component of the velocity is given by:
where
is the magnitude of the initial velocity
is the angle of the initial velocity with respect to the ground
Substituting numbers into the equation, we find
B. Vertical component: 14.3 m/s
Explanation:
The vertical component of the velocity is given by:
where
is the magnitude of the initial velocity
is the angle of the initial velocity with respect to the ground
Substituting numbers into the equation, we find
You can find
1) time to hit the ground
2) initial velocity
3) speed when it hits the ground
Equations
Vx = Vxo
x = Vx * t
Vy = Vyo + gt
Vyo = 0
Vy = gt
y = yo - Vyo - gt^2 / 2
=> yo - y = gt^2 / 2
1) time to hit the ground
=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2
=> t = √1.631 s^2 = 1.28 s
2) initial velocity
Vxo = x / t = 6.5m / 1.28s = 5.08 m/s
3) speed when it hits the ground
Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s
V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2
=> V = √ (183.56 m^2 / s^2) = 13.55 m/s
The log of 4311 is 8.3689251747471
Answer:
20 m/s
Explanation:
initial velocity, u= 25m/s
u has two components. one in horizontal and in one vertical.
so,
u sin theta = vertical component.
=> u sin theta = 25× 4/5
= 20 m/s
Answer:
y
Explanation:
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