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san4es73 [151]
3 years ago
11

_____ is the frictional force needed to slow an object in motion

Physics
2 answers:
s2008m [1.1K]3 years ago
8 0

Answer:

<u>Drag force</u> is the frictional force needed to slow an object in motion

Explanation:

const2013 [10]3 years ago
8 0

Answer:

Kinetic friction

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The linear momentum of a truck of mass 5000 kg that is moving at a velocity of +30 m/a is ___ kg m/s
miv72 [106K]

Linear momentum of a truck is 1,50,000 kg.m/s

Explanation:

Linear momentum is the product of the mass and velocity of an object. It is a vector quantity, which have a magnitude and a direction.

Linear momentum is a property of an object which is in motion with respect to a reference point (i.e. any object changing its position with respect to the reference point).

It's SI units are kg.m/s

Linear momentum is a vector quantity.

Linear momentum formula (p) = mass × velocity

Given data mass = 5000 kg ; velocity = 30 m/s

P = 5000 × 30

Linear momentum p= 1,50,000 kg.m/s

7 0
3 years ago
What must be true the number of chromosomes in each sex cell
zvonat [6]

Answer:

In humans, each cell normally contains 23 pairs of chromosomes, for a total of 46.

8 0
3 years ago
Look at the graph. What is the slope of the line?
NeTakaya

For the first hour, the slope is zero.

After that, the slope is -2 miles per hour.

7 0
2 years ago
A truck with 28-in.-diameter wheels is traveling at 50 mi/h. Find the angular speed of the wheels in rad/min, *hint convert mile
solong [7]

Answer:

Angular speed ω=3771.4 rad/min

Revolution=5921 rpm

Explanation:

Given data

d=28in\\r=d/2=28/2=14in\\v=50mi/hr

To find

Angular speed ω

Revolution per minute N

Solution

First we need to convert the speed of truck to inches per mile

as

1 mile=63360 inches

1 hour=60 minutes

so

v=(50*\frac{63360}{60} )\\v=52800in/min

Now to solve for angular speed ω by substituting the speed v and radius r in below equation

w=\frac{v}{r}\\ w=\frac{52800in/min}{14in}\\ w=3771.4rad/min

To solve for N(revolutions per minute) by substituting the angular speed ω in the following equation

N=\frac{w}{2\pi }\\ N=\frac{3771.4rad/min}{2\pi }\\ N=5921RPM  

3 0
3 years ago
PLEASE HELP. Really important
Kruka [31]

Explanation:

2) C would need the least effort, because the longer the effort distance, the least the effort applied.

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