The average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.
<h3>How to calculate the Average speed?</h3>
The average speed can be calculated by adding the speed of each trial divided by the number of trials,
For 0.25 m the average speed will be:

For the 0.50 m, the average speed will:

Therefore, the average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.
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Answer:
B hopefully this helps you with work
If the earth just doubles its size in an instant, the oxygen present in the atmosphere could be much larger. Due to these, we could theorize that insects could grow much larger because the size of their body is heavily dependent on the maximum amount of oxygen present in the atmosphere. Air pressure also increases thus those aerial enthusiasts would enjoy their professions.
Answer:
Time period of the osculation will be 2.1371 sec
Explanation:
We have given mass m = (B+25)
And the spring is stretched by (8.5 A )
Here A = 13 and B = 427
So mass m = 427+25 = 452 gram = 0.452 kg
Spring stretched x= 8.5×13 = 110.5 cm
As there is additional streching of spring by 3 cm
So new x = 110.5+3 = 113.5 = 1.135 m
Now we know that force is given by F = mg
And we also know that F = Kx
So 

Now we know that 
So 


Draw a free body vector diagram