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Anettt [7]
3 years ago
11

In column chromatography (microscale), after loading it with solvent and adsorbent and prior to loading the sample, what level s

hould you allow the solvent to drop to? Why should you not allow the sample to run dry and what is the consequence if you had allowed it to do so?Why would water not be used to elute a column (besides it polarity) in column chromatography?When isolating separated compounds from a column chromatography, what would aid in the identification of compounds in fractions in the TLC analysis?
Chemistry
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

Explanation:

You should allow the solvent to drop to the level of the adsorvent, so it would never run dry.

When you let your sample to run dry it will never finish to flow from the adsorbent depending of it polarity.

Water should not be used because it can dissolve the adsorbent.

You could use another technique to identify the compound, as an infrared or a ultraviolet detector. You can also, if you know the compounds, identify it for the retention time, for example, if you need to detect two compounds, one more polar than the other, and use a polar adsorbent and a non-polar solvent, the first compound to exit the column will be the less polar one, because it will have a bigger interaction with the solvent than the stationary phase (adsorbent) and will go faster, the second will be the more polar one, because it will have a bigger interaction with the stationary phase.

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State the functional groups that undergo cracking and substitution reaction.
omeli [17]

Unsaturated organic compounds with a carbon-to-carbon double bond and alkynes with a carbon-to-carbon triple bond, as well as aldehydes and ketones with a carbon-to-oxygen double bond, undergo addition reactions.

8 0
2 years ago
C12H26O + SO3+NaOH ----> C12H25NaSO4+ H2O
Vlad [161]

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

4 0
3 years ago
How do electrons transition between energy levels?
kow [346]
The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level.
7 0
3 years ago
HURRYYY !!!! What radioactive isotope produces Aluminum-13 by beta decay
fgiga [73]

Answer:

I DONT KNOW SORRY

Explanation:

7 0
3 years ago
Read 2 more answers
CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol
Zolol [24]

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

Concentration of the unknown acid

Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

M1V1 = M2V2

0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

Learn more about Concentration here:

brainly.com/question/17206790

#SPJ4

3 0
2 years ago
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