Hey there!:
1) The additional stability that accompanies the formation of the network<span>Crystalline is measured as network enthalpy.
</span>2) The reticular energy is the energy released when the solid Crystal isform from separate ions in the gaseous state. Always exothermic.<span>
3) </span>The enthalpy of the network depends directly on the size of the loads and conversely in the distance between the ions .
hope this helps!
I think the answer is a but I am not for sure
Answer:
The equivalent weight of M is approximately 31.8 g
The equivalent weight of N is approximately 27.98 g
Explanation:
The given parameters are;
The percentage of the the metal M in in the chloride = 47.25%
Where by the chemical formula for the metal chloride is MClₓ, we have;
47.25% of the mass of MClₓ = Mass of M = W
Therefore, we have;
![\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}](https://tex.z-dn.net/?f=%5Cdfrac%7B0.4725%7D%7BW%7D%20%3D%20%5Cdfrac%7B1%7D%7BW%20%2B%2035.5%20%5Ccdot%20x%7D)
0.4725 × (W + 35.5·x) = W
0.4725·W + 0.4725×35.5×x = W
W - 0.4725·W = 16.77·x
0.5275·W = 16.77·x
W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M
The equivalent weight of M = 31.799 ≈ 31.8 g
Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g
The equivalent weight of N = 27.98 g.
<u>Answer:</u> The reaction proceeds in the forward direction
<u>Explanation:</u>
For the given chemical equation:
![2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)](https://tex.z-dn.net/?f=2NO%28g%29%2BCl_2%28g%29%5Crightleftharpoons%202NOCl%28g%29)
Relation of
is given by the formula:
![K_p=K_c(RT)^{\Delta n_g}](https://tex.z-dn.net/?f=K_p%3DK_c%28RT%29%5E%7B%5CDelta%20n_g%7D)
where,
= equilibrium constant in terms of partial pressure = ?
= equilibrium constant in terms of concentration = ![6.5\times 10^4](https://tex.z-dn.net/?f=6.5%5Ctimes%2010%5E4)
R = Gas constant = ![0.0821\text{ L atm }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=0.0821%5Ctext%7B%20L%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
T = temperature = ![35^oC=[35+273]K=308K](https://tex.z-dn.net/?f=35%5EoC%3D%5B35%2B273%5DK%3D308K)
= change in number of moles of gas particles = ![n_{products}-n_{reactants}=2-3=-1](https://tex.z-dn.net/?f=n_%7Bproducts%7D-n_%7Breactants%7D%3D2-3%3D-1)
Putting values in above equation, we get:
![K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43](https://tex.z-dn.net/?f=K_p%3D6.5%5Ctimes%2010%5E4%5Ctimes%20%280.0821%5Ctimes%20500%29%5E%7B-1%7D%5C%5C%5C%5CK_p%3D1583.43)
is the constant of a certain reaction at equilibrium while
is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
The expression of
for above equation follows:
![Q_p=\frac{(p_{NOCl})^2}{p_{Cl_2}\times (p_{NO})^2}](https://tex.z-dn.net/?f=Q_p%3D%5Cfrac%7B%28p_%7BNOCl%7D%29%5E2%7D%7Bp_%7BCl_2%7D%5Ctimes%20%28p_%7BNO%7D%29%5E2%7D)
We are given:
![p_{NOCl}=1.76atm](https://tex.z-dn.net/?f=p_%7BNOCl%7D%3D1.76atm)
![p_{NO}=1.01atm](https://tex.z-dn.net/?f=p_%7BNO%7D%3D1.01atm)
![p_{Cl_2}=0.42atm](https://tex.z-dn.net/?f=p_%7BCl_2%7D%3D0.42atm)
Putting values in above equation, we get:
![Q_p=\frac{(1.76)^2}{0.42\times (1.01)^2}=7.23](https://tex.z-dn.net/?f=Q_p%3D%5Cfrac%7B%281.76%29%5E2%7D%7B0.42%5Ctimes%20%281.01%29%5E2%7D%3D7.23)
We are given:
![K_p=1583.43](https://tex.z-dn.net/?f=K_p%3D1583.43)
There are 3 conditions:
- When
; the reaction is product favored. - When
; the reaction is reactant favored. - When
; the reaction is in equilibrium
As,
, the reaction will be favoring product side.
Hence, the reaction proceeds in the forward direction
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Explanation:
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