Impure substance, because pure would be dirt from the earth
Answer and Explanation:
<em>A funnel is in the top of the buret and a beaker is positioned underneath the buret:</em> This is correct and is necessary to fill the buret, but the funnel and the beaker has to be removed before the titration starts. The calculation for moles of analyte does not affect.
<em>A solution is being poured from a bottle into the buret via the funnel:</em> Using a funnel helps to fill the burette but it must be removed to filling the buret at 0.0 mL. In this case, the calculation for moles of analyte do not affect.
<em>Adding titrant past the color change of the analyte solution</em>: In this case, an excess of titrant is added, thus the calculation for moles of anality will be higher than it should be.
<em>Recording the molarity of titrant as 0.1 M rather than its actual value of 0.01 M</em>: In this case, the titrant is considered more concentrated than it is hence, the calculation for moles of anality will be higher than it should be.
<em>Spilling some analyte out of the flask during the titration</em>: The excess of titrant spilled out of the flask higher up the volume of titrant measured. Therefore, the calculation for moles of anality will be higher than it should be.
<em>Starting the titration with air bubbles in the buret</em>: The air inside the burette occupies measured volume, thus the volume of titrant measured will be higher than the real volume spilled in the flask. Hence the calculation for moles of anality will be higher than it should be.
<em>Filling the buret above the 0.0 mL volume mark</em>: Some volume of titrant will be spilled inside the flask but will no be measured since the buret measures the titrant below the 0.0mL mark, thus the calculation for moles of anality will be lower than it should be.
M₁ *V₁ = M₂ * V₂
12.0 * V₁ = 6.0 * 500.0
12.0 V₁ = 3000
V₁ = 3000 / 12.0
V₁ = 250 mL
hope this helps!
Answer:
0.11 M
Explanation:
The computation of molarity of the CH3COOH solution is shown below:-
Where,
= Molarity of LioH = 0.0175
= Volume of LioH = 18.5 ml
= Volume of CH3COOH = 29.4 ml
Now, we will put the values into the formula
Which gives result
= 0.011 M
Therefore for computing the molarity of the CH3COOH solution we simply applied the above formula.
