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ivanzaharov [21]
3 years ago
7

2NaHCO3-->Na2CO3+H2O+CO2

Chemistry
1 answer:
algol [13]3 years ago
8 0
I’m not sure what kind of answer you’re looking for, but if you’re supposed to translate it into a sentence it would be two moles of sodium bicarbonate(baking soda) decompose unto one mole of sodium carbonate(soda ash) plus one mole of water and one mole of carbon monoxide gas
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Good morning, I have a question..
matrenka [14]

Answer:

<h3>The answer is 5.24 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 152 g

density = 29 g/cm³

We have

volume =  \frac{152}{29}  \\  = 5.24137931...

We have the final answer as

<h3>5.24 mL</h3>

Hope this helps you

7 0
3 years ago
Which statement correctly describes extreme weather?
sveta [45]

Answer: A

Explanation:

Extreme weather events follow normal climate patterns.

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3 years ago
What is the main product of the fusion reactions in our sun?
RUDIKE [14]
The sun generates its energy by nuclear fusion of hydrogen nuclei into helium.
8 0
3 years ago
2FeCl3 ---&gt; 2FeCl2 + Cl2
vesna_86 [32]
The correct options are as follows: 
1. In the chemical equation given above, Fe3+  IS REDUCED.
A reduction is a process in which an atom of an element gains an electron and therefore become reduced. In this type of reaction, the positive character of the atom is reduced. Looking at the equation given above, you will notice that, the positive character of Iron is reduced form +3 to +2.

2. In the reaction given above, the chlorine atom is OXIDIZED.
An oxidation is a process in which an atom loses an electron, thereby increasing its oxidation number. In this case, the positive character of the atom is increased. Looking at the chlorine atom given above, you will notice that it has a charge of -1 before and now it has change to neutral, which means that, it has given out the electron it gains earlier.

3. This type of redox reaction can not take place. This is because, in chemical reaction, the chlorine atom is always looking for another element that will donate an electron to it in order to become stable. Thus, chlorine atom easily gain electrons but it can not donate an electron to another element.<span />
8 0
3 years ago
Read 2 more answers
A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.
Andru [333]

Answer:  The empirical formula and the molecular formula of the organic compound is CHO and C_4H_4O_4 respectively.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2 = 21.71 g

Mass of H_2O= 5.926 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 21.71 g of carbon dioxide, =\frac{12}{44}\times 21.71=5.921g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 5.926 g of water, =\frac{2}{18}\times 5.926=0.658g of hydrogen will be contained.

Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53  g

Mass of C = 5.921 g

Mass of H = 0.658 g

Mass of O = 10.53 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles

Mass of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.493}{0.493}=1

For H =\frac{0.658}{0.493}=1

For O=\frac{0.658}{0.493}=1

The ratio of C : H: O =  1: 1: 1

Hence the empirical formula is CHO.

empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29

Molecular mass = 104.1 g/mol

n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4

Thus molecular formula = n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4

6 0
3 years ago
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