2NaHCO3-->Na2CO3+H2O+CO2
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Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J
Solution :
(1) The equation used is,
where,
= final internal energy
= initial internal energy
q = heat energy
w = work done
(2) The known variables are, q, w and
initial internal energy = = 2000 J
heat energy = q = 1000 J
work done = w = 500 J
(3) Now plug the numbers into the equation, we get
(4) By solving the terms, we get
(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J
