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Nuetrik [128]
4 years ago
8

Which of the following contains both ionic and covalent bonding?

Chemistry
2 answers:
djyliett [7]4 years ago
7 0
I believe the correct answer from the choices listed above is the first option. The compound that contains both ionic and covalent bonding is KOH or potassium hydroxide. It contains one covalent<span> (O-H) and one that is </span>ionic<span> (K-O). Hope this helps.</span>
pantera1 [17]4 years ago
6 0

Answer: KOH

Explanation:

Being KOH the only not binary compound it is the candidate to be the one with two different type of bondings.

In fact, KOH is a ionic compound because the cation K⁺ forms a ionic bond with the anion OH⁻.

On the other hand, the oxigen and hydrogen atoms in OH⁻ are covalently bonded.

The ionic bond is the result of the union of two atoms with a high elecronegativity difference, while the covalent bonding is the result of a combination of two atoms whose electronegativities is not so different.

Being K and alkali metal (the elements with lowest electronegativity) and OH⁻ an anion, they easily form the ionic bond.

From tables, the electronegativity of H is 2.20 and the electronegativity of O is 3.16, which leads to a difference of 3.16 - 2.20 = 0.96. This difference is not enough to form ions but covalent bonds. That is why the bond O-H is covalent.

When you analyze the bonds of the other choices, N-O, C-H, and H-Br, y ou conclude that the electronegativities lead to covalent bonds too.

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An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 eV, 27 eV, and 48 eV. What
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Answer:

l=3.5*10^{-10}m

Explanation:

From the question we are told that:

1st Energy     E_1=12eV=4(3eV)

2nd Energy  E_2=27eV=9(3eV)

3rd Energy   E_3=48eV=16(3eV)

 

Generally the equation for Energy E for electron in one dimensional box at ground state E_0 is mathematically given by

  E_0=\frac{h}{8ml^2}

  E_0=\frac{h}{8ml^2}

Therefore Length a is mathematically given as

l=\sqrt{\frac{h^2}{8mE_0} }

l=\sqrt{\frac{(6.625*10^{-34})^2}{8(9.1*19^{-31}{(3eV(1.6*10^{-19}))}}

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Answer:

Usually give off heat energy

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\Delta H is the enthalpy change;

\Delta S is the entropy change;

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In order to achieve a negative value in the Gibbs free energy change, we should have:

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This is true for all temperatures if:

\Delta H < 0, \Delta S > 0

The major term here is the change in enthalpy, notice that we wish the enthalpy change to be negative.

Negative enthalpy change corresponds to an exothermic reaction, the one which releases heat. This means exergonic reactions would usually give off heat.

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