Answer:
Freezing point of solution is -4.39°C
Explanation:
Freezing point depression's formula:
ΔT = Kf . m . i
ΔT = Freezing point of pure solvent - Freezing point of solution
0°C - X = 1.86°C/m . m . 2
i = Van't Hoff factor, ions dissolved in solution
MgCl₂ → Mg²⁺ + 2Cl⁻ i = 3 → 1 mol of Mg and 2 mol of chloride
Let's think the molality (mol/kg)
First of all, let's convert the mass of solvent from g to kg
100 g / 1000 = 0.1 kg
Molality (mol/kg) = 0.118 mol / 0.1 kg = 1.18 m
0°C - X = 1.86°C/m . 1.18 m . 2
X = - 4.39°C
Answer:
[O₃]= 8.84x10⁻⁷M
Explanation:
<u>The photodissociation of ozone by UV light is given by:</u>
O₃ + hν → O₂ + O (1)
<u>The first-order reaction of the equation (1) is:</u>
(2)
<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>
<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>
(3)
<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>
We can calculate the initial ozone concentration using equation (3):
So, the ozone concentration after 10 days is 8.84x10⁻⁷M.
I hope it helps you!
The role of the carbon dioxide in water is that it has the ability to form an acid in which it has the capacity to react with underground limestones deposits. If it is able to react with the limestone, then it will most likely produce a substance that can be water-soluble.
Answer for your question is;
2,6 = 8
The first shell is 2 electrons the other shell is 6 electrons