1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Amanda [17]
3 years ago
14

If you wanted to protect water from freezing, which of the compounds below would accomplish this best. NaNO3, Mg(NO3)2, or Al(NO

3)3
Chemistry
1 answer:
Korvikt [17]3 years ago
4 0
All of them are soluble salt.

First one dissociates into two ions.

The second one dissociates into 3 ions.

The third dissociate into 4 ions. therefore, Al(NO3)3
You might be interested in
I NEED HELP ASAP!!!
Rus_ich [418]

Explanation:

To answer this question, we'll need to use the Ideal Gas Law:

p

V

=

n

R

T

,

where

p

is pressure,

V

is volume,

n

is the number of moles

R

is the gas constant, and

T

is temperature in Kelvin.

The question already gives us the values for

p

and

T

, because helium is at STP. This means that temperature is

273.15 K

and pressure is

1 atm

.

We also already know the gas constant. In our case, we'll use the value of

0.08206 L atm/K mol

since these units fit the units of our given values the best.

We can find the value for

n

by dividing the mass of helium gas by its molar mass:

n

=

number of moles

=

mass of sample

molar mass

=

6.00 g

4.00 g/mol

=

1.50 mol

Now, we can just plug all of these values in and solve for

V

:

p

V

=

n

R

T

V

=

n

R

T

p

=

1.50 mol

×

0.08206 L atm/K mol

×

273.15 K

1 atm

= 33.6 L

this is not the answer but it will help you

do by the formula it is on the answer

3 0
3 years ago
Atoms in a gaseous state have
Mumz [18]
More energy than atoms in a liquid state
6 0
3 years ago
Read 2 more answers
An aqueous solution is found to be 3.64% potassium nitrate by mass, how many grams of solution should I evaporate the water from
Sidana [21]

Answer:

513.74 g of solution

Explanation:

% Mass grams are defined as the <em>grams that are dissolved in salt</em> (in this case, it would be <em>potassium nitrate</em>) <em>dissolved every 100 g of the solution</em>. Having this information, you can calculate the amount of solution that has dissolved 18.7 g of potassium nitrate, which is what we want to obtain.

The relationship is:

3.64 g of potassium nitrate _____ 100 g solution

18.7 g of potassium nitrate _____ X = 513.74 g of solution

Calculation: 18.7g x 100g / 3.64g = 513.74 g of solution

So, <em>I need 513.74 g of solution to get 18.7g of potassium nitrate by evaporating it</em>.

8 0
3 years ago
The number of protons plus the number of neutrons equal the ______
NARA [144]
the answer is: Atomic number
7 0
2 years ago
Read 2 more answers
Which compound is classified as a hydrocarbon?
Andrej [43]
<span>(2) butynu........................</span>
5 0
3 years ago
Read 2 more answers
Other questions:
  • What is the molality of a solution that is obtained by dissolving 2.922 g of NaCl into 1000.0 g of water if the molar mass of Na
    5·1 answer
  • Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the pr
    13·1 answer
  • Which subatomic particles would be found orbiting around the nucleus?
    5·1 answer
  • What did ancient astronomers think areas of the moon called mares might be?
    11·1 answer
  • Which of the following measurements is expressed to three significant figures? 7.30 × 10–7 km 0.007 m 7077 mg 0.070 mm
    13·1 answer
  • When does the composition of a substance does not change?
    12·1 answer
  • What element does sodium phosphate and silver nitrate create
    9·1 answer
  • What would the products be for the reaction between Na3PO4 + MgSO4?
    14·1 answer
  • StitchXpika plzzzzzzzzz
    15·1 answer
  • Which scenario supports the ""one gene–one enzyme"" hypothesis of metabolic disease causation?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!