Answer:
El termopar B presenta un mayor grado de dispersión y también es más preciso. ... (c) La estimación para T = 175 ° C es probablemente la más cercana al valor real, porque el ... (cm3). Flujo de masa. Velocidad. (kg / min). Diferencia. Duplicar. (Di). Yo y yo. 2. 1 ... atm de gas. 2. 2. 2 f. 3. 2 f f. 30 14,7 lb 20 pulg. 4 14,7 lb 24 pulg 392 lb 7,00 10 lb pulg.
Answer:
Your answer is triglycerides. Hope this helps.
Atoms or molecule after gaining of electron possesses negative charge and is known as anion.
For the given sets:
The given elements are alkali metals and have tendency to lose electrons easily and form cations.
The given elements are non-metals and are electronegative. So, they gain electrons easily and form anion.
Carbon has tendency to form bond by sharing of electrons, Sulfur has tendency to gain electrons and form anion whereas Lead has tendency to lose electron.
Potassium and Iron has tendency to lose electron and form cation whereas Bromine has tendency to gain electron to form anion.
Hence, from the given sets, all elements of set:
have tendency to form anions in binary ionic compounds.
Answer: the c thingy is where you be like burgundy sauce then be like racial slair is what it mean's so the name thingy
Explanation:
Metals like sodium, potassium, magnesium, etc. are extracted by electrolysis of their chlorides in molten state.
These metals are not extracted by reduction of their oxides with carbon because:
Carbon has less affinity for oxygen than these metals
Carbon is a weaker reducing agent than these metals
These metals easily form oxides with oxygen, their oxides are very stable. Affinity to the oxygen is one the greatest of all elements.
Reducing agent is element or compound who loose electrons in chemical reaction. Sodium, potassium, calcium and magnesium are very strong reducing agents because they easily loose one or two valence electrons.
Electrolysis is a chemical methode that uses electric currents for chemical reactions.
More about reducing agent: brainly.com/question/7484765
#SPJ4