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tatyana61 [14]
3 years ago
5

What’s a pnp transitor?

Engineering
2 answers:
Dafna1 [17]3 years ago
7 0

Answer:

A transistor is of two types: PNP and NPN

Explanation:

A transistor is current controlled device in which the current flow by the movement of the electrons and wholes.

The NPN and PNP transistor are the types of the BJT (Bipolar junction transistor) that have two uses i.e switching and amplification.

A PNP transistor have three junction i.e P, N and P where the base is connected to the N - junction. The P junction is high in number of wholes and N- junction have high numbers of electrons.

In the PNP transistor the voltage is provided to the emitter and base terminal with base connected to the negative terminal of the voltage source and emitter connected to its positive terminal. The direction of the flow of the current is from emitter to collector whenever a significant voltage is provided to the emitter base junction.  

Damm [24]3 years ago
6 0

Answer:

PnP transistor is a current controlled device. It has two crystal diodes connected back to back. The left side of the diode is known as the emitter-base diode and the other side which is the right side of the diode is known as the collector-base diode.

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Which of following are coding languages used in controlling a robot? *
Bess [88]

Answer:

C/C++

Explanation:

C/C++

7 0
3 years ago
How high a building could fire hoses effectively spray from the ground? Fire hose pressures are around 1 MPa. (It is also said t
Mrac [35]

Answer:

z_{2} = 91.640\,m

Explanation:

The phenomenon can be modelled after the Bernoulli's Principle, in which the sum of heads related to pressure and kinetic energy on ground level is equal to the head related to gravity.

\frac{P_{1}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}= z_{2}+\frac{P_{2}}{\rho\cdot g}

The velocity of water delivered by the fire hose is:

v_{1} = \frac{(300\,\frac{gal}{min} )\cdot(\frac{3.785\times 10^{-3}\,m^{3}}{1\,gal} )\cdot(\frac{1\,min}{60\,s} )}{\frac{\pi}{4}\cdot (0.3\,m)^{2}}

v_{1} = 0.267\,\frac{m}{s}

The maximum height is cleared in the Bernoulli's equation:

z_{2}= \frac{P_{1}-P_{2}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}

z_{2}= \frac{1\times 10^{6}\,Pa-101.325\times 10^{3}\,Pa}{(1000\,\frac{kg}{m^{3}} )\cdot(9.807\,\frac{m}{s^{2}} )} + \frac{(0.267\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )}

z_{2} = 91.640\,m

7 0
3 years ago
True or false a critique of hazwoper incidents that have occurred in the past year should not be included in hazwoper 8 hour ref
Jobisdone [24]

Answer:

False

Explanation:

No matter if something happened in the past year or so, it still should be included for safety reasons so it wont happen again

7 0
4 years ago
A transmission line (TL) of length L and conductance per unit length G' is connected to an ideal constant voltage generator V. T
Andru [333]

Answer:

The Current will decrease by a factor of 2

Explanation:

Given the conditions, it should be noted that the current in the circuit is determined by the LOAD. In other words, the amount of current generator will be producing depends upon the load connected to it.

Now, as the question says, the load is reduced to half its original value, we can write:

P1 = \sqrt{3} (V) (I1) Cos\alpha ----- (1)

P2 = \sqrt{3} (V) (I2) Cos\alpha\\

Since, P2 = P1/2,

P1/2 = \sqrt{3} (V) (I2) Cos\alpha ----- (2)\\

Dividing equations (1) and (2), we get,

P1 / (P1/2) = I1/ I2

I2 = I1 / 2\\

Hence, it is proved that the current in the transmission line will decrease by a factor of 2 when load is reduced to half.

7 0
3 years ago
If a weld is laying into a joint with a concave weld contour with undercutting issues, what might be the cause?
Katarina [22]

Answer:bbbb

Explanation:

4 0
3 years ago
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