is the volume of the sample when the water content is 10%.
<u>Explanation:</u>
Given Data:

First has a natural water content of 25% =
= 0.25
Shrinkage limit, 

We need to determine the volume of the sample when the water content is 10% (0.10). As we know,
![V \propto[1+e]](https://tex.z-dn.net/?f=V%20%5Cpropto%5B1%2Be%5D)
------> eq 1

The above equation is at
,

Applying the given values, we get

Shrinkage limit is lowest water content

Applying the given values, we get

Applying the found values in eq 1, we get


Answer:
The correct response is "821.88". A further explanation is given below.
Explanation:
According to the question,
The largest amount unresolved after five years would have been:
= 
= 
= 
Now,
time (t) will be:
= 
= 
So, monthly payment will be:
= 
= 
= 
Answer:
C
Explanation:
One of the disadvantages of solar cells is that electricity storage systems are not readily available. Excess energy generated by the solar panels are wasted except they are stored by solar batteries for later use. There are various systems for storing electricity from solar cells apart from solar batteries which is the common storage system. An example of another electricity storage system for solar cell is using the water electrolyzer to store solar energy which can be used to later generate hydroelectricity.
Advantages of a solar cell includes Renewable energy, Economy-friendly and environmental-friendly energy and good durability
Answer:
The speed of the sound for the adiabatic gas is 313 m/s
Explanation:
For adiabatic state gas, the speed of the sound c is calculated by the following expression:
Where R is the gas's particular constant defined in terms of Cp and Cv:
For particular values given:
The gamma undimensional constant is also expressed as a function of Cv and Cp:
And the variable T is the temperature in Kelvin. Thus for the known temperature:
The Jules unit can expressing by:
Replacing the new units for the speed of the sound:

Answer:
N = 38546.82 rpm
Explanation:
= 150 mm

= 17671.45 
= 250 mm

= 49087.78 
The centrifugal force acting on the flywheel is fiven by
F = M (
-
) x
------------(1)
Here F = ( -UTS x
+ UCS x
)
Since density, 





∴
-
= 50 mm
∴ F = 
F = 33618968.38 N --------(2)
Now comparing (1) and (2)

∴ ω = 4036.61
We know


∴ N = 38546.82 rpm