acts on a particle as the particle moves along an x axis, with in newtons, x in meters, and c a constant. At x = 0 m, the partic
1 answer:
Answer:
Explanation:
Assuming the following question: A force F = (cx 3.00x2 li acts on a particle as the particle moves along an x axis, with F in newtons, x in meters, and c a constant. At x = 0 m, the particle's kinetic energy is 22.0 J; at x = 4.00 m, it is 9.00 J. Find C.
Solution to the problem
We know that the work for this case since we don't have change of potential energy is given by:
Where KE means kinetic energy
And we know that the work can be expressed like this:
If we integrate the left part we got:
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Answer:
B. QC > 0; QH < 0
Explanation:
Given that there are two reservoir of energy.
Sign convention for heat and work :
1.If the heat is adding to the system then it is taken as positive and if heat is going out from the system then it is taken as negative.
2. If the work is done on the system then it is taken as negative and if the work is done by the system then it is taken as positive.
From hot reservoir heat is going out that is why it is taken as negative
From cold reservoir heat is coming inside the reservoir that is why it is taken as positive
That is why the answer will be
,
Answer:
1600 kJ/h per K, 888.88 kJ/h per °F and 888.88kJ/h per R
Explanation:
We make use of relations between temperature scales with respect to degrees celsius:
This means that a change in one degree celsius is equivalent to a change of one kelvin, while for a degree farenheit and rankine this is equivalent to a change of 1.8 on both scales.
So: