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andre [41]
1 year ago
7

A hiker walks due East for a distance of 6 km

Physics
1 answer:
solniwko [45]1 year ago
3 0

Resultant displacement between the base camp and the cave will be 7.211 km

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Her resultant displacement can be calculated using Pythagoras theorem

H^{2} = P^{2} + B^{2}

     = 4^{2} + 6^{2}

     = 52

H = \sqrt{52} = 7.211 km

Resultant displacement between the base camp and the cave will be 7.211 km

To learn more about displacement here :

brainly.com/question/13271165

#SPJ1

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Displacement is a vector magnitude that depends on the position of the body which is individualistic for the trajectory.

While, Distance is a scalar magnitude that measures over the trajectory.

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3 years ago
My sis needs help with this and I don't wanna help her!!! Can you guys help her????
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Answer and Explanation:

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3 years ago
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The initial kinetic energy imparted to a 0.25 kg bullet is 1066 J. The acceleration of gravity is 9.81 m/s 2 . Neglecting air re
lubasha [3.4K]

Answer:

The range of the bullet is 0.435 kilometers.

Explanation:

According to the problem, maximum height is equal to the range of the bullet. That is:

\Delta x = \Delta y

Where:

\Delta x - Range of the bullet, measured in meters.

\Delta y - Maximum height of the bullet, measured in meters.

By the Principle of Energy Conservation, gravitational potential energy reaches its maximum at the expense of the initial kinetic energy. That is to say:

K_{1} = U_{2}

Where:

K_{1} - Kinetic energy at point 1, measured in joules.

U_{1} - Gravitational potential energy at point 2, measured in joules, and:

U_{2} = m\cdot g \cdot \Delta y

Where:

m - Mass of the bullet, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

The maximum height is now cleared:

K_{1} = m\cdot g \cdot \Delta y

\Delta y = \frac{K_{1}}{m\cdot g}

If K_{1} = 1066\,J, m = 0.25\,kg and g = 9.81\,\frac{m}{s^{2}}, the maximum height is now computed:

\Delta y = \frac{1066\,J}{(0.25\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\Delta y = 434.791\,m

\Delta y = 0.435\,km

Lastly, the range of the bullet is 0.435 kilometers.

3 0
3 years ago
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Answer:

C is the right answer.

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3 years ago
Whats the speed of darkness?
lianna [129]
The same speed of light, the fastest possible

darkness is just the absence of light therefore once light leaves darkness returns. making darkness have the same speed of light
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