The magnetic field at center of circular loops of wire is 3.78 x 10¯⁵ T.
We need to know about the magnetic field at the center of circular loops of wire to solve this problem. The magnetic field at the center can be determined as
B = μ₀ . I / 2r
where B is magnetic field, μ₀ is vacuum permeability (4π×10¯⁷ H/m), I is the current and r is radius.
From the question above, we know that:
r = 4 cm = 0.04 m
I = 1.7 A
By substituting the parameter, we get
B = μ₀ . I / 2r
B = 4π×10¯⁷ . 1.7 / (2.0.04)
B = 2.67 x 10¯⁵ T
Due to the perpendicular plane of loops, the total magnetic field at center will be
Btotal = √(2(B²))
Btotal = √(2(2.67 x 10¯⁵²))
Btotal = 3.78 x 10¯⁵ T
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If it is s-t graph , point is c
if it is v-t graph , point is e
Answer: C ) 75 kilometers
Explanation: 30 + 45 = 75
Answer:
moving the circuit or the magnet gives the same result
Explanation:
The faraday effect establishes that the temporal variation of imaginative flow produces an electric potential
fem = dfi / dt
the magnetic flux is
Ф = B. A = B A cos θ
suppose for simplicity that the angle is zero so cos 0 = 1
Φ = B A
By analyzing this expression, the change in magnetic flux can converge while keeping the magnetic field fixed and varying the electric field or keeping the electric field fixed and varying the magnetic field.
Consequently moving the circuit or the magnet gives the same result
Answer:
Explanation:
Given:
- mass of the body stretching the spring,
- extension in spring,
- velocity of oscillation,
- initial displacement position of equilibrium,
<u>According to given:</u>
<u>we know frequency:</u>
Now, for position of mass in oscillation:
at
∴
∵ at